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3 years ago

Arrange from least to greatest. 5/6 2/4 5/12

Mathematics

1 answer:

Jet001 [13]3 years ago

6 0

Answer:

5/6=10/12. 2/4=6/12. 5/12

5/12. 2/4. 5/6

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Fit a quadratic function to these three points:<br> (-2,8), (0, -4), and (4, 68)<br> Respuesta

zloy xaker [14]

Answer:

f(x) = 4x^2 + 2x - 4.

Step-by-step explanation:

Let the quadratic function be y = f(x) = ax^2 + bx + c.

For the point (-2, 8) ( x = -2 when y = 8) we have:

a(-2)^2 + (-2)b + c = 8

4a - 2b + c = 8 For (0, -4) we have:

0 + 0 + c = -4 so c = -4. For (4, 68) we have:

16a + 4b + c = 68

So we have 2 systems of equations in a and b ( plugging in c = -4):

4a - 2b - 4 = 8

16a + 4b - 4 = 68

4a - 2b = 12

16a + 4b = 72 Multiplying 4a - 2b = 12 by 2 we get:

8a - 4b = 24

Adding the last 2 equations:

24a = 96

a = 4

Now plugging a = 4 and c = -4 in the first equation:

4(4) - 2b - 4 = 8

-2b = 8 - 16 + 4 = -4

b = 2.

3 0

3 years ago

Two students walk in the same direction along a straight path, at a constant speed - one at .90 m/s and the other at 1.90 m/s.a.

anyanavicka [17]

Answer:

a)The second student arrive 7 minutes and 36 seconds sooner

b)They have to walk 598,51 m

Step-by-step explanation:

Speed= Distance/Time

We are looking for time now

Time = Distance/Speed

First student

Time = 780 m/0.90 m/s=866,66 seconds

Second student

Time = 780 m/1.90 m/s=410,52 seconds

Difference=866,66-410,52= 456,14 seconds

In minutes

Difference= 456,14 seconds /60=7 minutes 36 seconds

Distance=Speed x Time

Speed¹ x Time¹ =Speed² x Time²

Time¹= Time² + 5.50 min

5.50 min =350 seconds

Time² =Speed¹ x Time¹ /Speed²

Time² =Speed¹ x (Time² + 350 seconds ) /Speed²

Time² =0.9 x (Time² + 350 seconds ) /1.9

Time² =0,4737 x (Time² + 350 seconds )

Time² =0,4737 Time² + 165,79 seconds

Time² - 0,4737 Time² = 165,79 seconds

0,5263 Time² = 165,79 seconds

Time² = 165,79 seconds/0,5263 =315,01 seconds

Distance=1,9 x 315,01 seconds = 598,51 m

5 0

3 years ago

The following system of equations can be used to

Damm [24]

Answer: • 6

• -4

•3

Step-by-step explanation:

8 0

3 years ago

Ned walks 6 tenths of a mile to school.Fred walks 9 tenths of a mile to school.who walks farther?.Explain

FromTheMoon [43]

Fred. .9 is larger than .6 therefore, Fred walked a longer distance.

8 0

3 years ago

Read 2 more answers

At her most recent race, Sue finished in 272 minutes. That is 15% less time than the previous race. What was her time in the pre

ValentinkaMS [17]

Answer:

320 minutes was her time on the previous race

Step-by-step explanation:

Let the time spent on the previous race be x minutes.

Given that at her most recent race, Sue finished in 272 minutes which is 15% less time than the previous race then

x - 15% * x = 272

x - 0.15x = 272

0.85x = 272

x = 272/0.85

x = 320 minutes

7 0

3 years ago