PLEASE HELP ME FAST!! I am close to a 100 so please don't give me a wrong answer.
1 answer:
Answer:
y = 8x
Step-by-step explanation:
1. First, we need to know what slope-intercept form is. The slope-intercept form of any linear equation is y = mx + b, where y = y-coordinate, m = slope, x = x-coordinate, and b = y-intercept.
2. To find the slope, let's take the two points (0,0) and (10,80) and plug their values into this formula:
3. Now that we know our slope, our equation should look like this so far: y = 8x + b.
4. Since b is the y-intercept, we can say that b = 0 because the line intersects with the y-axis at (0,0).
5. Therefore, we get an equation of y = 8x or y = 8x + 0.
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Solving this requires use of conversions
we already know that
2.05 m > 2 m
all that's left is the question
200 cm vs. 2.05 meters
I we know our equivalencies, we know that
100 cm = 1 m
if this is so then
200 cm = 2 m
we already know that
2.05 m > 2 m
so it must also be that
2.05 m > 200 cm
we already know that
2.05 m > 2 m
all that's left is the question
200 cm vs. 2.05 meters
I we know our equivalencies, we know that
100 cm = 1 m
if this is so then
200 cm = 2 m
we already know that
2.05 m > 2 m
so it must also be that
2.05 m > 200 cm
Answer:
(x + 6, y + 0), 180° rotation, reflection over the x‐axis
Step-by-step explanation:
The answer can be found out simply , a trapezoid has its horizontal sides usually parallel meanwhile the vertical sides are not parallel.
The horizontal parallel sides are on the x-axis.
Reflection over y- axis would leave the trapezoid in a vertical position such that the trapezoid ABCD won't be carried on the transformed trapezoid as shown in figure.
So option 1 and 2 are removed.
Now, a 90 degree rotation would leave the trapezoid in a vertical position again so its not suitable again.
In,The final option (x + 6, y + 0), 180° rotation, reflection over the x‐axis, x+6 would allow the parallel sides to increase in value hence the trapezoid would increase in size,
180 degree rotation would leave the trapezoid in an opposite position and reflection over x-axis would bring it below the Original trapezoid. Hence, transformed trapezoid A`B`C`D` would carry original trapezoid ABCD onto itself
