A single, standard number cube is tossed. What is the probability of getting a 4 or a 5?
2 answers:
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I am assuming the expression is (2x-3)(x+5) or (2x-3)(x-5). I will teach you how to solve for both as I am not sure which one you are asking for. There are 4 steps to multiplying.
1) Multiply the x times the second x
2) Multiply x times the second number
3) Multiply the number by the second x
4) Multiply the number by the second number.
(2x*x)+(2x*5)+(-3*x)+(-3*5)=(2
)+(10x)+(-3x)+(-15)=2+7x-15
(2x*x)+(2x*-5)+(-3*x)+(-3*-5)=(2)+(-10x)+(-3x)+(15)=2-13x+15
Your answer is 2+7x-15 or 2-13x+15. Does that answer your question?
1) Multiply the x times the second x
2) Multiply x times the second number
3) Multiply the number by the second x
4) Multiply the number by the second number.
(2x*x)+(2x*5)+(-3*x)+(-3*5)=(2
(2x*x)+(2x*-5)+(-3*x)+(-3*-5)=(2
Your answer is 2