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The point P(–4, 4) that is of the way from A to B on the directed line segment AB.
Solution:
The points of the line segment are A(–8, –2) and B(6, 19).
P is the point that bisect the line segment in .
So, m = 2 and n = 5.
By section formula:
P(x, y) = (–4, 4)
Hence the point P(–4, 4) that is of the way from A to B on the directed line segment AB.