So since, they are the same distance from zero, they should be the oppposite of each other so in other words, k=-h and h=-k
so k+h=(subisute)k-k=-h+h=0 because they cancel
With any equation you are allowed to take the logarithm of both sides so
5^c=125 now take the logarithm base 5 to both sides giving.
log5(5^c)=log5(125), using the rule log(a^b)=a*log(b) you get
c log5(5)=log5(125), since log5(5)=1
c=log5(125)
Answer:
the factor is an increasing value of 17/332 or the power of pointed answers of interest of 3.4% which makes it aroujd 2 but doesnt matter because its the factor and not issued investment
Step-by-step explanation:
<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>:</em><em>)</em>
39x^3 = 13*3*x*x*x
-6x^2 = 2*3*x*x*-1
-3x = 3*x*-1
so in all these factorizations, 3*x is common. so 3x is the common factor.
by seperating the common factor,
3x(13x^2 - 2x-1)
will be the factorization.
xy + 5x - 5y - 25
=x (y+5) -5 (y+5)
=(x-5) (y+5)
hope I helped ya!!!
