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denis23 [38]
3 years ago
13

Tell me how do you find out how many Calendar days are in 7 standard years

Mathematics
1 answer:
larisa86 [58]3 years ago
7 0
2556.6975 days

Your answer would be
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Evaluate 3x for x = -2, x = 1, and x = 3.
marusya05 [52]
Option A is correct.

Put the values of x in 3^x and you will get the answer corresponding to option A
5 0
1 year ago
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Seven more than the product of a number and <br> 8<br> is equal to <br> 5
yuradex [85]
8x + 7 = 5

A "product" is the result of a multiplication operation.  So the product of a number, ( which we will call x,) and 8 would be 8x. (Or 8*"x" number) 7 more than that product would be 8x + 7 = 5

Hope that this helps!
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3 years ago
PLEASE HELP FAST WILL MARK BRAINLIEST!!!!!!
puteri [66]

Answer: the second one

Step-by-step explanation:

5 0
3 years ago
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I don't know how to solve it.
Nataly [62]

Step-by-step explanation:

Take the first derivative

\frac{d}{dx} ( {x}^{3}  - 3x)

3 {x}^{2}  - 3

Set the derivative equal to 0.

3 {x}^{2}  - 3 = 0

3 {x}^{2}  = 3

{x}^{2}  = 1

x = 1

or

x =  - 1

For any number less than -1, the derivative function will have a Positve number thus a Positve slope for f(x).

For any number, between -1 and 1, the derivative slope will have a negative , thus a negative slope.

Since we are going to Positve to negative slope, we have a local max at x=-1

Plug in -1 for x into the original function

( - 1) {}^{3}  - 3(  - 1) = 2

So the local max is 2 and occurs at x=-1,

For any number greater than 1, we have a Positve number for the derivative function we have a Positve slope.

Since we are going to decreasing to increasing, we have minimum at x=1,

Plug in 1 for x into original function

{1}^{3}   - 3(1)

1 - 3 =  - 2

So the local min occurs at -2, at x=1

8 0
2 years ago
A set of four stars form the shape of a rectangle in space. The length of the rectangle is approximately 2,290,000 miles, while
ANTONII [103]

Answer:

89

Step-by-step explanation:

1800beetlejuice

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