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QveST [7]
3 years ago
15

Plsss help! <3 (science)

Chemistry
1 answer:
Umnica [9.8K]3 years ago
3 0

Answer:

The answer is C. Gamma rays are the highest energy electromagnetic waves in the electromagnetic ... Show the heat released by astronomical objects 3. Detect collection of gas, dust, and plasma. Which of these best matches the waves with their applications? ... C) Gamma rays—1 and infrared waves—2

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eleanor wants to show her class a comparison of melting rates between two different solids when he is applied why would a graph
sashaice [31]

Eleanor wants to show her class a comparison of melting rates between two different solids when heat is applied. A graph would be more suitable than a table to show her data because the she can see the trend line of the effects of melting than the table.

7 0
3 years ago
In general is it better to measure a large or small sample
Sveta_85 [38]
Large samples... also can be small as well but usually bigger is better
5 0
3 years ago
Pls help tysm &lt;3 :D:D
Marianna [84]
Not sure about 2 or 3 but I believe that for number 1 is B or claim 2!!
5 0
3 years ago
Mg(s) + Cu(NO3)2(aq) → Mg(NO3)2(aq) + Cu(s)
Rus_ich [418]

Answer: increase

Explanation: when Mg is powder it has greater surface area and

Reaction occurs faster

3 0
3 years ago
A 93-L sample of dry air is cooled from 145 oC to -22 oC at a constant pressure of 2.85 atmospheres). What is the final volume?
vlada-n [284]

Answer:

56 L

Explanation:

We're dealing with a gas in this problem. We may, therefore, apply the ideal gas law for this problem:

pV = nRT

We now that we have a constant pressure. Besides, R, the ideal gas law constant, is also a constant number. Let's rearrange the equation so that we have all constant variables on the right and all changing variables on the left:

\frac{V}{T} = \frac{nR}{p} = const

This means the ratio between volume and temperature is a constant number. For two conditions:

\frac{V_1}{T_1} = \frac{V_2}{T_2}

Given initial volume of:

V_1 = 93 L

Convert the initial temperature into Kelvin:

T_1 = 145^oC + 273.15 K = 418.15 K

Convert the final temperature into Kelvin:

T_2 = -22^oC + 273.15 K = 251.15 K

Rearrange the equation for the final volume:

V_2 = V_1 \cdot \frac{T_2}{T_1} = 93 L\cdot \frac{251.15 K}{418.15 K} = 56 L

8 0
4 years ago
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