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3 years ago

Which has a higher boiling point n2 or o2

Chemistry

1 answer:

Basile [38]3 years ago

4 0

o2 because n2 is a pretty low bowling point.

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qwelly [4]

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3 years ago

A substance that makes things taist sweeter

elena-s [515]

Sugar. (We need a design tech section)

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4 years ago

Which of the following is a strong base?

malfutka [58]

C. NaOH ammmonia is also an base but not as strong as NaOH

3 0

3 years ago

question 11 use the internet to look up the sds for 2.0 m sodium hydroxide, naoh, to answer the following questions: a) list the

frozen [14]

The compound is basic in nature but the concentration substance is corrosive.

Sodium hydroxide is a compound that is formed from sodium and hydrogen as well as oxygen The compound is basic in nature but the concentration substance is corrosive.

a) The acute health effect of exposure to NaOH is skin burn while the chronic effect of exposure is damage to the lungs.

b) The first aid for the ingestion of NaOH is to take in plenty of water.

c) The compound is not flammable

d) The chemicals that could produce a dangerous reaction with NaOH are acids

e) To handle small spills, irrigate the affected area with plenty water and use lab coats, gloves and eye wear when working with the solution.

Learn more about sodium hydroxide:brainly.com/question/24010534

#SPJ1

5 0

2 years ago

Compounds A, B, and C react according to the following equation. 3A(g) + 2B(g) 2C(g) At 100°C a mixture of these gases at equili

Vedmedyk [2.9K]

Answer:

The value of Kc for the reaction is 3.24

Explanation:

A reversible chemical reaction, indicated by a double arrow, occurs in both directions: reagents transforming into products ( direct reaction) and products transforming back into reagents (inverse reaction)

Chemical Equilibrium is the state in which direct and indirect reactions have the same reaction rate. Then taking into account the rate constant of a direct reaction and its inverse the chemical constant Kc is defined.

Being:

aA + bB ⇔ cC + dD

where a, b, c and d are the stoichiometric coefficients, the equilibrium constant with the following equation:

$Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a} *[B]^{b} }$

Kc is equal to the multiplication of the concentrations of the products raised to their stoichiometric coefficients divided by the multiplication of the concentrations of the reagents also raised to their stoichiometric coefficients.

Then, in the reaction 3A(g) + 2B(g) ⇔ 2C(g), the constant Kc is:

$Kc=\frac{[C]^{2} }{[A]^{3} *[B]^{2} }$

where:

[A]= 0.855 M
[B]= 1.23 M
[C]= 1.75 M

Replacing:

$Kc=\frac{1.75^{2} }{0.855^{3}*1.23^{2} }$

Solving you get:

Kc=3.24

<u><em>The value of Kc for the reaction is 3.24</em></u>

8 0

3 years ago