How to solve this problem im not getting a good answer

Mathematics

2 answers:

Margaret [11]3 years ago

8 0

1) rewrite x^2-9 in the form a^2-b^2, where a=x and b=3.
4 over x+3 + 3 over x^2-3^2

2)Use difference of squares
4 over x+3 + 3 over (x+3)(x-3)

3) Cross multiply
4(x-3)+3 over (x+3)(x-3)

4) Expand
4x-12+3 over (x+3)(x-3)

5) Simplify 4x-12+34x−12+3 to 4x-94x−9
4x-9 over (x+3)(x-3)

kow [346]3 years ago

7 0

Well, you have to simplify the bottom part to be able to answer it as a whole number. Hope this helps.

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Pls can someone help me <img src="https://tex.z-dn.net/?f=%20log10%20%5Csqrt%7B36%7D%20%20%2B%20%20%20%20log10%20%20%5Csqrt%7

Firlakuza [10]

Answer:

$= log_{10}(\frac{6\sqrt{2} }{\sqrt{7} } )$

Step-by-step explanation:

Given the expression $log10\sqrt{36} + log10\sqrt{2} - log10\sqrt{7} \\$

According to the law of logarithm;

loga + log b = log(ab) and log a - log b = log(a/b)

The given expression becomes;

$log10\sqrt{36} + log10\sqrt{2} - log10\sqrt{7} \\= log_{10}(\frac{\sqrt{36} \times \sqrt{2} }{\sqrt{7} })\\= log_{10}(\frac{6\sqrt{2} }{\sqrt{7} } )$