Answer:
y=3x-9
Step-by-step explanation:
Answer: 0.70
Step-by-step explanation:
Given : The random variable X, representing the number of accidents in a certain intersection in a week, has the following probability distribution:
x 0 1 2 3 4 5
P(X = x) 0.20 0.30 0.20 0.15 0.10 0.05
Using the above probability distribution , the the probability that in a given week there will be at most 3 accidents is given by :_
Hence, the required probability = 0.70
Answer:
depends on situations
Step-by-step explanation:
Answer:
2 touchdowns, 3 field goals
Step-by-step explanation:
The number of touchdowns cannot be more than 3, so it is relatively easy to find the solution by trial and error.
23 is not divisible by 3, so 0 touchdowns is not a solution
23 -7 = 16 is not divisible by 3, so 1 touchdown is not a solution
23 -14 = 9 is divisible by 3, so 2 touchdowns and 3 field goals is a solution
21 -21 = 2 is not divisible by 3, so there is only one solution.
When solving an equation with an absolute value term, you make two separate equations ans solve for x:
Equation 1: |4x-3|-5 = 4
1st add 5 to both sides:
|4x-3| = 9
Remove the absolute value term and make two equations:
4x-3 = 9 and 4x - 3 = -9
Solving for x you get X = 3 and x = -1.5
When you replace x with those values in the original equation the statement is true so those are two solutions.
Do the same thing for equation 2:
|2x+3| +8 = 3
Subtract 8 from both sides:
|2x+3| = -5
Remove the absolute value term and make two equations:
2x +3 = -5
2x+3 = 5
Solving for x you get -1 and 4, but when you replace x in the original equation with those values, the statement is false, so there are no solutions.
The answer is:
C. The solutions to equation 1 are x = 3, −1.5, and equation 2 has no solution.
