All categories

3 years ago

1821.5/0.7 ... can someone please explain and answer this? Thank you SO much!!

Mathematics

1 answer:

S_A_V [24]3 years ago

8 0

So you cant have a decimal in your divisor which means the problem sill become 18215/7 if that helps

You might be interested in

Help me w this math question! pleaseee

Ulleksa [173]

Answer:

the anwer is b

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Isaiah already has 16 dollars. Every hour (x) that he works at the bakery, he earns another 4 dollars (y). How many total dollar

Lena [83]

$68
4x13=52 + 16 = 68

5 0

3 years ago

Read 2 more answers

Which graph shows y=3⌈x⌉+1 ?

hram777 [196]

The graph located in the upper right corner of the image attached shows the graph of y = 3[x]+1.

In order to solve this problem we have to evaluate the function y = 3[x] + 1 with a group of values.

With x = { -3, -2, -1, 0, 1, 2, 3}:

x = -3

y = 3[-3] + 1 = -9 + 1

y = -8

x = -2

y = 3[-2] + 1 = -6 + 1

y = -5

x = -1

y = 3[-1] + 1 = -3 + 1

y = -2

x = 0

y = 3[0] + 1 = 0 + 1

y = 1

x = 1

y = 3[1] + 1 = 3 + 1

y = 4

x = 2

y = 3[2] + 1 = 6 + 1

y = 7

x = 3

y = 3[3] + 1 = 9 + 1

y = 10

x y

-3 -8

-2 -5

-1 -2

0 1

1 4

2 7

3 10

The graph that shows the function y = 3[x] + 1 is the one located in the upper right corner of the image attached.

7 0

3 years ago

Read 2 more answers

You have learned some new ways in this module to prove that triangles are similar Please describe some of these new postulates a

Finger [1]

Answer:

TA = 6 units

GT = 10 units

Step-by-step explanation:

Angle G is common to both triangles, so that's a congruent angle.

Since RT is parallel to EA,

Angle R = Angle E

And

Angle T = Angle A

When two triangles have the same distribution of angles, they are similar (by AAA).

Therefore GRT and GEA are similar

GE/GR = GA/GT

8/5 = 16/(16-x)

16-x = 16 × 5/8

16 - x = 10

x = 16 - 10

x = 6

GT = 16 - x = 16 - 6 = 10

5 0

3 years ago

The life in hours of a biomedical device under development in the laboratory is known to be approximately normally distributed.

tatuchka [14]

Answer:

a)Null hypothesis:- H₀: μ> 500

Alternative hypothesis:-H₁ : μ< 500

b) (5211.05 , 5411.7)

95% lower confidence bound on the mean.

c) The test of hypothesis t = 5.826 >1.761 From 't' distribution table at 14 degrees of freedom at 95% level of significance.

Step-by-step explanation:

Step :-1

Given a random sample of 15 devices is selected in the laboratory.

size of the small sample 'n' = 15

An average life of 5311.4 hours and a sample standard deviation of 220.7 hours.

Average of sample mean (x⁻) = 5311.4 hours

sample standard deviation (S) = 220.7 hours.

Step :- 2

a) Null hypothesis:- H₀: μ> 500

Alternative hypothesis:-H₁ : μ< 500

Level of significance :- α = 0.95 or 0.05

b) The test statistic

$t = \frac{x^{-} - mean}{\frac{S}{\sqrt{n-1} } }$

$t = \frac{5311.4 - 500}{\frac{220.7}{\sqrt{15-1} } }$

t = 5.826

The degrees of freedom γ= n-1 = 15-1 =14

tabulated value t =1.761 From 't' distribution table at 14 degrees of freedom at 95% level of significance.

calculated value t = 5.826 >1.761 From 't' distribution table at 14 degrees of freedom at 95% level of significance.

Null hypothesis is rejected at 95% confidence on the mean.

C) The 95% of confidence limits

$(x^{-} - t_{0.05} \frac{S}{\sqrt{n} } ,x^{-} + t_{0.05}\frac{S}{\sqrt{n} } )$

substitute values and simplification , we get

$(5311.4 - 1.761 \frac{220.7}{\sqrt{15} } ,5311.4 +1.761\frac{220.7}{\sqrt{15} } )$

(5211.05 , 5411.7)

95% lower confidence bound on the mean.

5 0

3 years ago