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guajiro [1.7K]
3 years ago
12

Lucy runs 6 miles in 50 minutes. At the same rate, how many miles would she run in 35 minutes?

Mathematics
2 answers:
Semenov [28]3 years ago
7 0

Answer:

She runs about 4.2 miles.

Step-by-step explanation:

6/50 = x/35

6*35 = 50*x

210 = 50x

50x = 210

x = 210/50

x = 4.2

She runs about 4.2 miles.

PilotLPTM [1.2K]3 years ago
3 0
6/50=x/35
50x=210
x= 4.2
Answer in thirty five minutes Lucy would run 4.2 miles
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Replace x with 10 and simplify the fraction.

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Julie ran 32.4 miles in May and 35.8 miles in June. Greg ran the same total distance as Julie, but only ran 29.6 miles in May. H
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Ede4ka [16]

Answer:

1) The mean calculated for this case is \bar X=61.5

2)  61.5-5.4=56.1

3) 61.5+5.4=66.9

4) B. An interval estimate gives us a sense of the accuracy of the point estimate whereas a point estimate alone does not.

Because with the confidence interval we know the confidence level of the interval, and the limits for the parameter at some significance level.  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Part 1

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (a)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (b)  

The mean calculated for this case is \bar X=61.5

The sample deviation calculated s=5.143

\mu population mean (variable of interest)

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Part 2

The confidence interval for the mean is given by the following formula:

\bar X \pm ME   (1)

So if we have the margin of error 5.4mm we can find the lowr limit like this:

61.5-5.4=56.1

Part 3

61.5+5.4=66.9

Part 4

B. An interval estimate gives us a sense of the accuracy of the point estimate whereas a point estimate alone does not.

Because with the confidence interval we know the confidence level of the interval, and the limits for the parameter at some significance level.

4 0
4 years ago
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Answer:

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8 0
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Answer:

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8 0
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