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IgorC [24]
3 years ago
7

Suppose y varies directly with x. write an equation relating x and y. y=7 when x=42

Mathematics
1 answer:
WARRIOR [948]3 years ago
5 0

Answer:

y = \frac{1}{6} x

Step-by-step explanation:

Given y varies directly with x then the equation relating them is

y = kx ← k is the constant of variation

To find k use the given condition that y = 7 when x = 42

k = \frac{y}{x} = \frac{7}{42} = \frac{1}{6}

y = \frac{1}{6} x ← equation of variation

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Serhud [2]

Answer:

44.94

Step-by-step explanation:

Use trigonometric ratios to find the unknown side.

Since you are given the adjacent side and the opposite side is in question, use the tangent ratio.

tan(x) = opposite/adjacent

Replace the variables with given values.

tan(59) = x/27

Isolate the variable.

27tan(59) = x

Use a calculator to evaluate the answer.

x = 27tan(59) ≈ 44.94

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8 0
3 years ago
Who could help me solve this?<br><br> Y=log x<br><br> If y=10, then what is x?
Viktor [21]

Step-by-step explanation:

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3 years ago
Find the area of following rhombuses. Round your answers to the nearest tenth if<br> necessary.
polet [3.4K]

Answer:

Area =55.4ft^2

Step-by-step explanation:

Given

The attached rhombus

Required

The area

First, calculate the length of half the vertical diagonal (x).

Length x is represented as the adjacent to 60 degrees

So, we have:

\tan(60) = \frac{4\sqrt 3}{x}

Solve for x

x = \frac{4\sqrt 3}{\tan(60)}

\tan(60) = \sqrt 3

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x = \frac{4\sqrt 3}{\sqrt 3}

x = 4

At this point, we have established that the rhombus is made up 4 triangles of the following dimensions

Base = 4\sqrt 3

Height = 4

So, the area of the rhombus is 4 times the area of 1 triangle

Area = 4 * \frac{1}{2} * Base * Height

Area = 4 * \frac{1}{2} * 4\sqrt 3 * 4

Area =2 * 4\sqrt 3 * 4

Area =55.4ft^2

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