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Georgia [21]
4 years ago
12

What does rate of change mean

Mathematics
1 answer:
jeka944 years ago
8 0

Answer:

A rate of change is a rate that describes how one quantity changes in relation to another quantity.

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3 years ago
The lateral edge PA of a triangular pyramid ABCP is perpendicular to the base and PA = 2sqrt5 in. The base edges AB = 10 in, AC
DIA [1.3K]

Answer:

PQ = √84 = 2√21 in ≈ 9.165 in

Step-by-step explanation:

The base edges AB = 10 in, AC = 17 in, and BC = 21 in

Q ∈ BC and AQ is the altitude of the base.

Let BQ = x in ⇒ CQ = (21 - x) in

ΔAQB a right triangle at Q

∴ AQ² = AB² - BQ² = 10² - x²  ⇒(1)

ΔAQC a right triangle at Q

∴ AQ² = AC² - CQ² = 17² - (21-x)²  ⇒(2)

Equating (1) and (2)

∴  10² - x² = 17² - (21-x)²

∴ 10² - x² = 17² - (21² - 42x + x²)

∴  10² - x² = 17² - 21² + 42x - x²

∴ 10² - 17² + 21² = 42x

∴ 42x = 252

∴ x = 252/42 = 6

Substitute at (1)

∴ AQ² = AB² - BQ² = 10² - x² = 100 - 36 = 64 = 8²

∴ AQ = 8 in

∵ The lateral edge PA of a triangular pyramid ABCP is perpendicular to the base

∴ PA⊥AQ

∴ ΔPAQ is a right triangle at A,

PA = 2sqrt5 in  and AQ = 8 in

∴ PQ (hypotenuse) = √(PA² + AQ²)

∴ PQ = √[(2√5)² + 8²] = √(20+64) = √84 = 2√21 in ≈ 9.165 in

6 0
3 years ago
PLEASE HELP! 20 PTS!
bekas [8.4K]
Power Property because log\sqrt[3]{x} = log x^{ \frac{1}{3} } = (1/3)logx;
6 0
3 years ago
Read 2 more answers
Given: ΔABC is a right triangle. Prove: a2 + b2 = c2 The following two-column proof with missing justifications proves the Pytha
Anestetic [448]

Answer:

Transitive property of equality is not a justification for the proof.

Step-by-step explanation:

We draw a right angle ΔACB. CD is perpendicular to AB.

Let AC = a , BC = b , AB = c and CD = h

Now in ΔABC and ΔACD

∠C = ∠D and ∠A = ∠A

from AA similarity postulate

ΔABC  similar to ΔACD.

Hence,

           \frac{c}{a} = \frac{a}{x}

           a^{2} = c × x ·····················(1)

Now in ΔABC and ΔCBD

∠C = ∠D and ∠B = ∠B

from AA similarity postulates

ΔABC similar to ΔCBD

Hence,

           \frac{c}{b} = \frac{b}{y}

           b^{2} = c × y······················(2)

Add equation (1) and (2)

      a^{2} + b^{2} = cx + cy

      a^{2} + b^{2} = c(x+y)

      a^{2} + b^{2} = c^{2}               [because x+y=c]

Transitive property is not useful for this proof.

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3 years ago
Y2 + 15y + 56 = (y + 7)(y +
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19y+63 is the correct answer
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3 years ago
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