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Sphinxa [80]
3 years ago
13

(10x + 10) (6x-8) What is the value of x?

Mathematics
1 answer:
suter [353]3 years ago
8 0

Answer:

<u>x= -9/2</u>

Step-by-step explanation:

(10x+10)=(6x-8)

10x-6x+10=-8

10x-6x=-8-10

4x=-18

<u>x= -9/2 </u>

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The largest side of a triangle is six more units than the smallest side. The third side is twice the smallest side. If the perim
svetlana [45]
Equation:     x + x + 6 = 2x = 25
smallest side is    4.75 units
largest size is      4.75 + 6 = 10.75 units
3rd side is           2(4.75)= 9.5 units

smallest side is    x 
largest size is      x + 6
3rd side is           2x
-----------------------------------
                           4x + 6 = 25 
                                  -6     -6
                             <u>4x</u> = <span><u>19</u>
</span>                             4        4

x = 4.75 is the smallest side


smallest side is    4.75 units
largest size is      4.75 + 6 = 10.75 units
3rd side is           2(4.75)= 9.5 units

7 0
2 years ago
The sum of first three terms of a finite geometric series is -7/10 and their product is -1/125. [Hint: Use a/r, a, and ar to rep
Alchen [17]
Ooh, fun

geometric sequences can be represented as
a_n=a(r)^{n-1}
so the first 3 terms are
a_1=a
a_2=a(r)
a_2=a(r)^2

the sum is -7/10
\frac{-7}{10}=a+ar+ar^2
and their product is -1/125
\frac{-1}{125}=(a)(ar)(ar^2)=a^3r^3=(ar)^3

from the 2nd equation we can take the cube root of both sides to get
\frac{-1}{5}=ar
note that a=ar/r and ar²=(ar)r
so now rewrite 1st equation as
\frac{-7}{10}=\frac{ar}{r}+ar+(ar)r
subsituting -1/5 for ar
\frac{-7}{10}=\frac{\frac{-1}{5}}{r}+\frac{-1}{5}+(\frac{-1}{5})r
which simplifies to
\frac{-7}{10}=\frac{-1}{5r}+\frac{-1}{5}+\frac{-r}{5}
multiply both sides by 10r
-7r=-2-2r-2r²
add (2r²+2r+2) to both sides
2r²-5r+2=0
solve using quadratic formula
for ax^2+bx+c=0
x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}
so
for 2r²-5r+2=0
a=2
b=-5
c=2

r=\frac{-(-5) \pm \sqrt{(-5)^2-4(2)(2)}}{2(2)}
r=\frac{5 \pm \sqrt{25-16}}{4}
r=\frac{5 \pm \sqrt{9}}{4}
r=\frac{5 \pm 3}{4}
so
r=\frac{5+3}{4}=\frac{8}{4}=2 or r=\frac{5-3}{4}=\frac{2}{4}=\frac{1}{2}

use them to solve for the value of a
\frac{-1}{5}=ar
\frac{-1}{5r}=a
try for r=2 and 1/2
a=\frac{-1}{10} or a=\frac{-2}{5}


test each
for a=-1/10 and r=2
a+ar+ar²=\frac{-1}{10}+\frac{-2}{10}+\frac{-4}{10}=\frac{-7}{10}
it works

for a=-2/5 and r=1/2
a+ar+ar²=\frac{-2}{5}+\frac{-1}{5}+\frac{-1}{10}=\frac{-7}{10}
it works


both have the same terms but one is simplified

the 3 numbers are \frac{-2}{5}, \frac{-1}{5}, and \frac{-1}{10}
6 0
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Which are whole numbers ? 0,4,-2,2/3,-1.8,16,3.2,-5/4
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Answer:

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Step-by-step explanation:

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