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3 years ago

What is the negative square root of 25 100 ?

Mathematics

2 answers:

Anna11 [10]3 years ago

6 0

Negative square root of 25 is -5
Negative square root of 100 is -10

WINSTONCH [101]3 years ago

5 0

Answer:

-5 and -10

Step-by-step explanation:

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A sweatshirt that was originally priced at $42.50 has been marked down to $34.00. What is the percent decrease?

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The answer is 20%

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3 years ago

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1 - G;

2 - R;

3 - E;

4 - D;

5 - T;

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Step-by-step explanation:

The formula for calculating the sum of interior angles is ( n − 2 ) * 180 ∘ where n is the number of sides.

1) (4 - 2) * 180 = 360 therefore X + 100 + 118 + 53 = 360 => X = 360 - 100 - 118 - 53 = 89 => X = 89

2) (5 - 2) * 180 = 540 => 90 + 90 + X + 128 + X = 540 => 2*X = 540 - 90 - 90 - 128 = 232 => X = 116

3) (6 - 2) * 180 = 720 => 101 + 126 + X + 96 + 147 + 135 = 720 => X = 720 - 101 - 126 - 96 - 147 - 135 = 115 => X = 115

4) (9 - 2) * 180 = 7 * 180, since all angles are equal the answer is 7 * 180 / 9 = 7 * 20 = 140 => X = 140

5) (5 - 2) * 180 = 540 => 90 + 131 + 102 + X + 145 = 540 => X = 540 - 90 - 131 - 102 - 145 = 72 => X = 72

6) Since the sum of the linear pair angles equal 180, X = 180 - 70 = 110 => X = 110

7) (4 - 2) * 180 = 360; Linear pair angle for 73 is 180 - 73 = 107, that means X + 102 + 39 + 107 = 360 => X = 360 - 102 - 39 - 107 = 112 => X = 112

8) (5 - 2) * 180 = 540; Linear pair angle for 84 is 180 - 84 = 96; Linear pair angle for 79 is 180 - 79 = 101; Linear pair angle for 34 is 180 - 34 = 146; so X + 90 + 96 + 101 + 146 = 540 => X = 540 - 90 - 96 - 101 - 146 = 107 => X = 107

4 0

3 years ago

It cost 5 dollars for a child ticket and 8 dollars for a adult ticket. Total tickets sold were 110 bringing in 820 dollars? How

omeli [17]

Number of child tickets bought is 20

<h3><u>Solution:</u></h3>

Given that It cost 5 dollars for a child ticket and 8 dollars for a adult ticket

cost of each child ticket = 5 dollars

cost of each adult ticket = 8 dollars

Let "c" be the number of child tickets bought

Let "a" be the number of adult tickets bought

Total tickets sold were 110 bringing in 820 dollars

<em>Number of child tickets bought + number of adult tickets bought = 110</em>

c + a = 110 ----- eqn 1

<em><u>Also we can frame a equation as:</u></em>

Number of child tickets bought x cost of each child ticket + number of adult tickets bought x cost of each adult ticket = 820

$c \times 5 + a \times 8 = 820$

5c + 8a = 820 -------- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "c" and "a"

From eqn 1,

a = 110 - c ------ eqn 3

Substitute eqn 3 in eqn 2

5c + 8(110 - c) = 820

5c + 880 - 8c = 820

-3c = - 60

c = 20

Therefore from eqn 3,

a = 110 - 20 = 90

a = 90

Therefore number of child tickets bought is 20

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Step-by-step explanation:

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Suppose the man in the St. Ives poem has x wives, each wife has x sacks, each sack has x cats, and each cat has x kits. Write an

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Answer:

$x^{1}$ wives

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$x^{3}$ cats

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Suppose the man in the St. Ives poem has x wives, each wife has x sacks, each sack has x cats, and each cat has x kits. Write an expression using exponents that represents the total number of kits, cats, sacks, and wives going to St .Ives.

Step-by-step explanation:

$x^{1}$ wives

If each of the "x" wives has "x" sacks, so the number of sacks is:

$x^{2}$ sacks

If each of the "x" wives has "x" sacks, and each sack has "x" cats, so the number of cats is:

$x^{3}$ cats

If each of the "x" wives has "x" sacks, and each sack has "x" cats, and each cat has "x" kits, so the number of kits is:

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