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3 years ago

Solve the system y = -x + 7 and y = 0.5(x - 3)2 explain the answer

Mathematics

1 answer:

ehidna [41]3 years ago

4 0

Answer:

x=5, x=-1

Step-by-step explanation:

Since both equations are equal to y, we can set them equal to each other

y = -x + 7 and y = 0.5(x - 3)2

-x + 7 = 0.5(x - 3)^2

Distribute the right hand side by Foiling

-x+7 =.5 ( x^2 -3x-3x+9)

Combine like terms

-x+7 = .5( x^2 -6x+9)

Distribute the .5

-x+7 = .5x^2 -3x+4.5

Add x to each side

-x+x+7 = .5x^2 -3x+x+4.5

7 = .5x^2 -2x+4.5

Subtract 7 from each side

7 -7= .5x^2 -2x+4.5-7

0 = .5x^2 -2x-2.5

Multiply by 2 to clear the decimals

0 = x^2 -4x -5

Factor

0 = (x-5) (x+1)

Using the zero product property

x-5=0 x+1 =0

x=5, x=-1

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NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.

Oliga [24]

Answer:

$\displaystyle 1)48.2 \: \: \text{sec}$

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Step-by-step explanation:

<h3>Question-1:</h3>

so when flash down occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

$\displaystyle - 4.9 {t}^{2} + 229t + 346 = 0$

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$\displaystyle x = \frac{ - b \pm \sqrt{ {b}^{2} - 4 ac} }{2a}$

so let our a,b and c be -4.9,229 and 346 Thus substitute:

$\rm\displaystyle t = \frac{ - (229) \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

remove parentheses:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

simplify square:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}$

simplify multiplication:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 6781.6} }{ - 9.8}$

simplify Substraction:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 45659.4} }{ - 9.8}$

by simplifying we acquire:

$\displaystyle t = 48.2 \: \: \: \text{and} \quad - 1.5$

since time can't be negative

$\displaystyle t = 48.2$

hence,

at 48.2 seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

$\displaystyle x _{ \text{max}} = \frac{ - b}{2a}$

let a and b be -4.9 and 229 respectively thus substitute:

$\displaystyle t _{ \text{max}} = \frac{ - 229}{2( - 4.9)}$

simplify which yields:

$\displaystyle t _{ \text{max}} = 23.4$

now plug in the maximum t to the function:

$\rm \displaystyle h(23.4)- 4.9 {(23.4)}^{2} + 229(23.4)+ 346$

simplify:

$\rm \displaystyle h(23.4) = 3021.6$

hence,

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