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3 years ago

Solve. −5.1p + 3.8 = 86.93

Mathematics

1 answer:

Bess [88]3 years ago

5 0

Answer: p = -16.3

Step-by-step explanation:

86.93 - 3.8 = 83.13

83.13/-5.1 = -16.3

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10. The continuously compounded annual return on a stock is normally distributed with a mean of 20% and standard deviation of 30

ehidna [41]

Answer: We should expect its actual return in any particular year to be between -40% and 80%.

Step-by-step explanation:

Given : The continuously compounded annual return on a stock is normally distributed with a mean 20% and standard deviation of 30%.

From normal z-table, the z-value corresponds to 95.44 confidence is 2.

Therefore , the interval limits for 95.44 confidence level will be :

Lower limit = Mean -2(Standard deviation) = 20% -2(30%)= 20%-60%=-40%

Upper limit = Mean +2(Standard deviation)=20% +2(30%)= 20%+60%=80%

Hence, we should expect its actual return in any particular year to be between -40% and 80%.

7 0

3 years ago

What is the equation for the line of reflection?

cestrela7 [59]

Answer:

i believe it is y=x

Step-by-step explanation:

3 0

3 years ago

What is the value of x that makes this figure correct? *

ruslelena [56]

Answer:

Step-by-step explanation:

Opposite angles are equal so

4x+12=44

4x=32

x=8

5 0

3 years ago

Determine the slope-intercept form of the equation of the line parallel to y = x + 11 that passes through the point[-6,2]

Mashutka [201]

I think the answer is: y-2=1(x-(-6))

5 0

3 years ago

Can someone help please I need this asap

son4ous [18]

Answer:

PART:A

$10_P_4=5040$

PART:B

$6_C_2=15$

PART:C

$6_C_2=15$

Step-by-step explanation:

PART:A

When the four officers are chosen than the number of ways of doing this is:

$10_P_4$

since we have to choose 4 officers and also they need to be arranged according to their ranks.

Hence, the numbers of ways doing so is:

$10_P_4=\dfrac{10!}{(10-4)!}\\\\=\dfrac{10!}{6!}\\\\=10\times 9\times 8\times 7\\\\=5040$

PART:B

Now we have to choose 2 members out of the remaining 6 members so the we have to use combination since we have to just choose the members and do not have to rank them or in short we can say we do not have to arrange them.

Hence, the number of ways doing this is:

$6_C_2=\dfrac{6!}{2!\times (6-2)!}\\\\=\dfrac{6!}{2!\times 4!}\\\\=15$

Hence, the number of ways of doing this is: 15.

PART:C

Now this process of doing so is also same as the above.

Hence, the number of ways of doing so is: 15.

8 0

3 years ago