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3 years ago

What is the slope of the line that contains the points (-2,1) and (0,-3)

Mathematics

2 answers:

LenaWriter [7]3 years ago

5 0

Answer:

ans is -2

Step-by-step explanation:

(-3-2)/(0+2)=-2

alexira [117]3 years ago

4 0

Slope form
Y2-y1/ x2-x1

-3-1/0-(-2) = -4/2

The answer is -2
Hope this helps!

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Verify that your point from Question 2 is a solution to 2x-y=-12x−y=−1 AND is also a solution to y=5x-5y=5x−5. What does it mean

Vera_Pavlovna [14]

Answer:

(a) Verified

(b) They are simultaneous equations

Step-by-step explanation:

Given

$2x - y = -1$

$y =5x - 5$

Required

Verify that: $(x,y) = (2,5)$ is a solution

We have:

$2x - y = -1$

Substitute: $(x,y) = (2,5)$

$2 * 2 - 5 = -1$

Evaluate all products

$4 - 5 = -1$

Subtract:

$-1 = -1$

Because both sides of the equation are equal, then the point is a solution

Also: $y =5x - 5$

Substitute: $(x,y) = (2,5)$

$5 = 5 * 2 - 5$

Evaluate all products

$5 = 10 - 5$

Subtract:

$5 = 5$

Because both sides of the equation are equal, then the point is a solution

Because the given point is a solution to both equations, then they are simultaneous equation

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3 years ago

find the slope of the line containing the points (-1,6) and (3,5) put final.answer in slope-intercept form

Ugo [173]

Given the points (-1,6) and (3,5).

The formula to find the slope is

$m=\frac{y_2-y_1_{}}{x_2-x_1}$

Take

$x_1=-1,y_1=6,x_2=3,y_2=5$

Plug the values into the formula and find the slope.

$\begin{gathered} m=\frac{5-6}{3-(-1)} \\ =\frac{-1}{4} \end{gathered}$

The slope-intercept form is y = mx+b.

Plug the value of m.

$y=-\frac{1}{4}x+b$

ThusConsider the point (-1,6). Substitute -1 for x and for y into the equation.

$\begin{gathered} 6=-\frac{1}{4}(-1)+b \\ =\frac{1}{4}+b \\ b=6-\frac{1}{4} \\ =\frac{23}{4} \end{gathered}$

Thus, the equation of the line in slope intercept form is

$y=-\frac{1}{4}x+\frac{23}{4}$

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Answer:

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Step-by-step explanation:

20x40%=8

$20-$8=$12

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