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luda_lava [24]
3 years ago
9

Going against the current, a boat takes 6 hours to make a 120-mile trip. When the boat travels with the current on the return tr

ip, it takes 5 hours. If x = the rate of the boat in still water and y = the rate of the current, write an expression that represents the rate of the boat going with the current. Type the expression in the space provided. Type only lowercase letters and do not use spaces in your answer
Mathematics
1 answer:
Andrew [12]3 years ago
5 0

Answer:

120 miles/6 hours = 20 mph. You need to do the same for the boat going with the current. 120 miles/ 5 hours = 24 mph.

Step-by-step explanation:

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Answer:

Step-by-step explanation:

Step 1: What are the couch's original coordinates?

  • A: (-4, 2)
  • N: (-4, 3)
  • G: (-1, 3)
  • L: (-1, 4)
  • E: (-5, 4)
  • S: (-5, 2)

Step 2: Rotate the couch 90° counterclockwise.

Rule: (x, y) → (-y, x)

  • A': (-4, 2) → (-2, -4)
  • N': (-4, 3) → (-3, -4)
  • G': (-1, 3) → (-3, -1)
  • L': (-1, 4) → (-4, -1)
  • E': (-5, 4) → (-4, -5)
  • S': (-5, 2) → (-2, -5)

Step 3: Now reflect the "new" couch over the y-axis.

Rule: (x, y) → (-x, y)

  • A'': (-2, -4) → (2, -4)
  • N'': (-3, -4) → (3, -4)
  • G'': (-3, -1) → (3, -1)
  • L'': (-4, -1) → (4, -1)
  • E'': (-4, -5) → (4, -5)
  • S'': (-2, -5) → (2, -5)

Step 4: Finally translate the new new" couch right 1 unit and up 5 units.

Rule: (x + 1, y + 5)

  • A''': (2, -4) → (2 + 1, -4 + 5) → (3, 1)
  • N''': (3, -4) → (3 + 1, -4 + 5) → (4, 1)
  • G''': (3, -1) → (3 + 1, -1 + 5) → (4, 4)
  • L''': (4, -1) → (4 + 1, -1 + 5) → (5, 4)
  • E''': (4, -5) → (4 + 1, -5 + 5) → (5, 0)
  • S''': (2, -5) → (2 + 1, -5 + 5) → (3, 0)

Step 5: Use the distance formula to show that the length of EG is the same as the length of E'''G'''.

  • EG: (-5, 4)(-1, 3)
  • E'''G''': (5, 0)(4, 4)

Distance between E(-5, 4) and G(-1, 3)

  • x₁ = -5
  • x₂ = -1
  • y₁ = 4
  • y₂ = 3

\large \textsf {d = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$}\\\\\large \textsf {d = $\sqrt{(-1-(-5))^2+(3-4)^2}$}\\\\\large \textsf {d = $\sqrt{(-1+5)^2+(3-4)^2}$}\\\\\large \textsf {d = $\sqrt{4^2+(-1)^2}$}\\\\\ \large \textsf {d = $\sqrt{16+1}$}\\\\\large \textsf {d = $\sqrt{17}$}\\\\\large \textsf {d = ${4.12}$}

Distance between E'''(5, 0) and G'''(4, 4)

  • x₁ = 5
  • x₂ = 4
  • y₁ = 0
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\large \textsf  {d = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$}\\\\\large \textsf {d = $\sqrt{(4-5)^2+(4-0)^2}$}\\\\\large \textsf {d = $\sqrt{(-1)^2+4^2}$}\\\\\large \textsf {d = $\sqrt{1+16}$}\\\\\ \large \textsf {d = $\sqrt{17}$}\\\\ \large \textsf {d = ${4.12}$}

This means that the length of EG is the same as the length of E'''G'''.

Hope this helps!

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Step-by-step explanation:

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