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denis-greek [22]

3 years ago

8

Which decimal is less than 0.8 and greater than 0.02 A.0.81 B.0.46 C.0.86 D.0.006

1 answer:

vlada-n [284]3 years ago

5 0

I think it's D do you do k12

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Please answer this question

AfilCa [17]

Answer:

it is C

Step-by-step explanation:

4 0

2 years ago

Help PLZZZZZZZ:)))))

Scilla [17]

The answer is D. First add 2k, then divide by a, the subtract x, then divide by -1

4 0

4 years ago

The late fee for library books is 2.00 plus 15c each day for a book that is late.if Monica's late fee is 2.75 write and slove a

sergeinik [125]

X=2.00+15x
2.75=2.00+15x
-2.00 -200
75=15x
Divide each side by 15
x=5

3 0

3 years ago

Consider the sequence defined recursively by do = 0, an = an-1 + 3n – 1. a) Write out the first 5 terms of this sequence,

creativ13 [48]

Answer:

The first 5 terms of the sequence is 2,7,15,26,40.

Step-by-step explanation:

Given : Consider the sequence defined recursively by $a_0=0$ $a_n=a_{n-1}+3n-1$

To find : Write out the first 5 terms of this sequence ?

Solution :

$a_n=a_{n-1}+3n-1$ and $a_0=0$

The first five terms in the sequence is at n=1,2,3,4,5

For n=1,

$a_1=a_{1-1}+3(1)-1$

$a_1=a_{0}+3-1$

$a_1=0+2$

$a_1=2$

For n=2,

$a_2=a_{2-1}+3(2)-1$

$a_2=a_{1}+6-1$

$a_2=2+5$

$a_2=7$

For n=3,

$a_3=a_{3-1}+3(3)-1$

$a_3=a_{2}+9-1$

$a_3=7+8$

$a_3=15$

For n=4,

$a_4=a_{4-1}+3(4)-1$

$a_4=a_{3}+12-1$

$a_4=15+11$

$a_4=26$

For n=5,

$a_5=a_{5-1}+3(5)-1$

$a_5=a_{4}+15-1$

$a_5=26+14$

$a_5=40$

The first 5 terms of the sequence is 2,7,15,26,40.

5 0

3 years ago

Round 0.977 to the nearest hundredth

UkoKoshka [18]

.98 since the hundredth place is higher than a five it is rounded up

5 0

3 years ago