Tan(x) = opp/adj
tan(30°) = 9/n
n x √3/3 = 9
3n x √3 = 27
3√3n = 27
√3n = 9
n = 9/√3
6x + 6 > 3x+ 15
3x > 9
x > 3
Answer:
We can not solve for a unique cost for each soldier.
Step-by-step explanation:
Let x be the daily cost for legionaries and y be the daily cost for archers.
Upon using our given information we will get a system of linear equations as:


Now we will solve for x from our 2nd equation,

Now we will substitute this value in our 1st equation.

We can see that -3y cancels out with 3y and 9 is not equal to 10. So this is an unsolvable system. Therefore, we can not find a unique cost for each soldier.
Answer:
Step-by-step explanation:
(9 + m)(-m + 9) = (9 + m)(9 - m) {(a+b)(a-b) = a² - b²}
= 9² - m²
= 81 - m²
= -m² + 81