The mean temperature for the first 4 days in January was 1°C.

Mathematics

1 answer:

schepotkina [342]3 years ago

8 0

Answer:

The temperature on the 5th day was of -9ºC.

Step-by-step explanation:

Mean of a data-set

The mean of a data-set is the sum of all values in the data-set divided by the number of values.

The mean temperature for the first 4 days in January was 1°C.

This means that during the first 4 days, the sum of the temperatures was 4*1 = 4ºC.

The mean temperature for the first 5 days in January was -1°C.

First 4 days: Sum of 4º

5th day: Temperature of x.

The mean is -1, so:

$-1 = \frac{4 + x}{5}$

$x + 4 = -5$

$x = -9$

The temperature on the 5th day was of -9ºC.

You might be interested in

X^2 + 5x = quadratic equation <br>=

timama [110]

Hi there!

The question gives us the quadratic equation , and it tells us to solve it using the quadratic formula, which goes as . However, we must first find the values of a, b, and c. The official quadratic equation goes as , which matches the format of the given quadratic equation. Hence, the value of a would be 1, the value of b would be 5, and the value of c would be 3. Now, just plug it back into the quadratic equation and simplify to get the zeros of the equation.

x = \frac{-b \pm \sqrt{b^2 - 4ac} }{2a}

x = \frac{-(5) \pm \sqrt{(5)^2 - 4(1)(3)} }{2(1)}

x = \frac{-5 \pm \sqrt{25 - 12} }{2}

x = \frac{-5 \pm \sqrt{13} }{2}

x = \frac{-5 \pm 3.61 }{2}

x = \frac{-5 + 3.61 }{2}, x = \frac{-5 - 3.61 }{2}

x=-0.695 \ \textgreater \ \ \textgreater \ -0.7, x= -4.305 \ \textgreater \ \ \textgreater \ x=-4.31

Therefore, the solutions to the quadratic equation are x = -0.7 and x = -4.31. Hope this helped and have a phenomenal day!

Your answer is 4.31

4 0

3 years ago

On which number line are -3 and it’s opposite shown?