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Reil [10]
4 years ago
15

What is the evaluate of |-6.2|.

Mathematics
1 answer:
Marysya12 [62]4 years ago
6 0

Answer:

6.2

Step-by-step explanation:

The lines represent absolute value, all  your doing is changing it to a positive number which is 6.2

If the question asked What is the evaluate of I6.2I, the answer would be 6.2, it is always a positive number

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I need help on my homework it’s finding angles measures.
Fittoniya [83]

Answer:

48

Step-by-step explanation:

7 0
3 years ago
to start to solve the system of equations below, which number would you multiply in the equation -2x-5y=-1? The two equations ar
Rashid [163]

Answer:

You would multiply the x component by -2

Step-by-step explanation:

(-2) (-2x-5y)=-2(-1)

4x+10y=2

4x+2y=8

set both equal to 4x

4x=2-10y

4x=8-2y

2-10y=8-2y

-6=8y

y=-6/8

y=-3/4

4x + 2(-3/4) = 8

4x=38/4

x=38/16

x=19/8


4 0
3 years ago
Can anyone turn 3.25x+6.50y=520 into slope intercept form? pls!
Lynna [10]

Answer:

y=-1/2x+80

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A right cubic prism has edges of 3 1/4 inches. How many cubes with side lengths of 1/4 inches would be needed to fill the prism?
choli [55]
<span>(195/8)/(1/64) = (195/8)(64) = 1560 cubes is your answer.</span>
3 0
3 years ago
Fast hurry skdifhg did did do fish is​
Amiraneli [1.4K]

Answer:

-\frac{7}{10}

Step-by-step explanation:

Given:

\frac{1}{2}- 1 \frac{1}{5}

Number line is from range -2 to 2 with all increment of ±\frac{2}{10} on both sides.

Step 1: First we will solve the equation we will get;

\frac{1}{2}- 1 \frac{1}{5}\\\\\frac{1}{2}- \frac{6}{5}

Step 2: Now we will try to make the denominator common so we will get;

\frac{1\times 5}{2\times 5}- \frac{6\times 2}{5\times 2}\\\\\frac{5}{10}- \frac{12}{10}

Step 3: Now from the number line when we subtract \frac{12}{10}

from \frac{5}{10} we get number of spaces left are - 7

Hence now it will become:

\frac{5}{10}- \frac{12}{10}\\\\\frac{5 -12}{10}\\\\-\frac{7}{10}

Hence the final Answer is -\frac{7}{10}

4 0
3 years ago
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