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Monica [59]
3 years ago
8

Fast hurry skdifhg did did do fish is​

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
4 0

Answer:

-\frac{7}{10}

Step-by-step explanation:

Given:

\frac{1}{2}- 1 \frac{1}{5}

Number line is from range -2 to 2 with all increment of ±\frac{2}{10} on both sides.

Step 1: First we will solve the equation we will get;

\frac{1}{2}- 1 \frac{1}{5}\\\\\frac{1}{2}- \frac{6}{5}

Step 2: Now we will try to make the denominator common so we will get;

\frac{1\times 5}{2\times 5}- \frac{6\times 2}{5\times 2}\\\\\frac{5}{10}- \frac{12}{10}

Step 3: Now from the number line when we subtract \frac{12}{10}

from \frac{5}{10} we get number of spaces left are - 7

Hence now it will become:

\frac{5}{10}- \frac{12}{10}\\\\\frac{5 -12}{10}\\\\-\frac{7}{10}

Hence the final Answer is -\frac{7}{10}

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Answer:

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1/8 + 2(1/2m + 5) = 1/4m + 7
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A ribbon is 12 3/8 feet long.Into how many 3/4-foot pieces can it be cut?
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__  ÷     __
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Find the area of the shaded region.f(x)=4x+3x2−x3,g(x)=0<br> The area is _____.
Tasya [4]

Answer:

The answer is " \bold{\frac{7}{2}}"

Step-by-step explanation:

Given value:

\to f(x)=4x+3x^2-x^3\\\\\to g(x)=0

Find:

area=?

calculation:

\ Area = \int_{-1}^{0} -(4x+3x^2-x^3) dx  + \int_{0}^{1} (4x+3x^2-x^3) dx  \\\\

        =  -(2x^2+x^3- \frac{x^4}{4})_{-1}^{0} + (2x^2+x^3- \frac{x^4}{4})_{0}^{1}\\\\\\=  -( 2x^2+x^3- \frac{x^4}{4})_{-1}^{0} + (2x^2+x^3- \frac{x^4}{4})_{0}^{1}\\\\\\= ( 2- 1 -\frac{1}{4}) + (2+1- \frac{1}{4})\\\\\\=  ( \frac{8-4-1}{4}) + (\frac{8+4-1}{4})\\\\=  ( \frac{3}{4}) + (\frac{11}{4})\\\\=   \frac{3}{4} + \frac{11}{4}\\\\= \frac{11+3}{4}\\\\= \frac{14}{4}\\\\= \frac{7}{2}\\\\

7 0
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