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Alex Ar [27]
2 years ago
15

Plot the x intercepts,maxima and minima of y=cos(x) from 0 to 2pi

Mathematics
1 answer:
erik [133]2 years ago
4 0

Answer:

Figure of the function is included below as attachment.

Step-by-step explanation:

Let y = \cos xAs first step we have to find x intercepts, maxima and minima from 0 to 2π, which are needed to plot given function. Cosine is a trigonometric function bounded between -1 and 1 with a periodicity of 2π.

x-Intercepts

x-intercepts are those points of the function such that y = 0. That is:

\cos x = 0

In this case, there is a periodicity of π for y = 0. The x-intercepts are in the following set:

S = \{\forall\,x\in\mathbb{R}|x=0.5\pi\pm\pi\cdot i,i\in\mathbb{N}_{O} \}

Maxima

Maxima are those points of the function such that y = 1. That is:

\cos x = 1

In this case, there is a periodicity of 2π for y = 1. Maxima are in the following set:

S = \{\forall\,x\in\mathbb{R}|x=0\pm2\pi\cdot i,i\in\mathbb{N}_{O} \}

Minima

Minima are those points of the function such that y = -1. That is:

\cos x = -1

In this case, there is a periodicity of 2π for y = -1. Minima are in the following set:

S = \{\forall\,x\in\mathbb{R}|x=\pi\pm2\pi\cdot i,i\in\mathbb{N}_{O} \}

Lastly, we proceed to plot the function as well as its x-intercepts, maxima and minima with the help of a plotting tool.

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Hi there!  

»»————- ★ ————-««

I believe your answer is:  

Option A

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

\boxed{\text{Option A:}}\\\\3^{-5}\\\\\rightarrow \frac{1}{3^5}\\\\\rightarrow  \frac{1}{243}\\\\\ \text{This is \textbf{NOT} an integer.}}

⸻⸻⸻⸻

\boxed{\text{Option B:}}\\\\-3^5\\\\\rightarrow -3 * -3 * -3 * -3 * -3 \\\\\rightarrow \boxed{-243}\\\\\\\text{This \textbf{IS} an integer.}

⸻⸻⸻⸻

\boxed{\text{Option C:}}\\\\\frac{1}{3}^{-5} \\\\\rightarrow \frac{1}{(\frac{1}{3})^5}\\\\\rightarrow \frac{1}{\frac{1}{243} }\\\\\rightarrow \boxed{243}\\\\\\\text{This \textbf{IS} an integer.}

⸻⸻⸻⸻

\text{Option \textbf{A} does not simplify into an integer.}

⸻⸻⸻⸻

»»————- ★ ————-««  

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