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I am Lyosha [343]
3 years ago
9

Solve for x. s=3w+2x

Mathematics
1 answer:
trapecia [35]3 years ago
6 0
W equal -2/3x+1/3s and that’s it
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A recreation center offers a membership for $75. Members may take classes for $10 each. nonmembers must pay $15 for these classe
Papessa [141]
If a member pays for 3 classes it will be $30 and if a nonmember for 2 classes it will be $30 dollars as well. Also, if a member pays for 6 classes it will be $60 and if a nonmember pays 4 classes it will be $60 as well
3 0
3 years ago
VODU
garri49 [273]

Answer:

r = ∛(3V/4π)

Step-by-step explanation:

The formula for the volume of a sphere is V = (4/3)πr³.

We want to solve this first for r³ and then for r.

Multiplying both sides of V = (4/3)πr³ by 3 yields an equation without fractions:  3V = 4πr³.

Dividing both sides of this equation by 4π isolates r³:

       3V

r³ = -------

       4π

To find r, take the cube root of both sides of

       3V

r³ = -------

       4π

obtaining r = ∛(3V/4π)

3 0
3 years ago
Read 2 more answers
The table shows the number of cups of water required when cooking different amounts of rice.
swat32

Answer:

  • The amount of water is the dependent value.
  • The amount of rice is the independent value.

Step-by-step explanation:

The wording "the amount of water required for different amounts of rice" suggests that the "output" value of the table is the amount of water, and the "input" value is the amount of rice.

That makes "water" the <em>dependent</em> variable, and "rice" the <em>independent</em> variable.

  The amount of water is the dependent value.

  The amount of rice is the independent value.

4 0
3 years ago
Read 2 more answers
Who wants to hangouttt :)
swat32

Answer:

Step-by-step explanation:

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6 0
2 years ago
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Pre-calc, image attached
makvit [3.9K]

Answer:

\lim_{x \to 7} \frac{\sqrt{x+2}-3 }{x-7} = \frac{1}{6}

Step-by-step explanation:

\lim_{x \to 7} \frac{\sqrt{x+2}-3 }{x-7}

\frac{\sqrt{x+2}-3 }{x-7}

\frac{\frac{1}{2} (x+2)^{-\frac{1}{2} }}{1} <-- Take derivative of numerator and denominator expressions

{\frac{1}{2} (x+2)^{-\frac{1}{2} }} <-- Simplify

\frac{1}{2}(\frac{1}{\sqrt{x+2} }) <-- Rewrite

\frac{1}{2}(\frac{1}{\sqrt{7+2} }) <-- Use direct substitution and plug in the limit x=7

\frac{1}{2}(\frac{1}{\sqrt{9} })

\frac{1}{2}(\frac{1}3 })

\frac{1}{6}

Therefore, \lim_{x \to 7} \frac{\sqrt{x+2}-3 }{x-7} = \frac{1}{6}

4 0
2 years ago
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