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3 years ago

13

Dominique is a customer of Apexoria Credit Union. She has $22,978 in a checking account and $20,000 in savings. How much of Domi

niques money is FDIC-protected? A. $20,000 B. $42,978 C. $250,000 D. $0

1 answer:

Dafna1 [17]3 years ago

7 0

Actually the answer is D

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Find the measure of the angle formed by the hands of a clock when it is 7:00 (the angle formed between 7 to 12, clockwise).

aev [14]

The answer you are looking for is an obtuse so it would be more than 90 degrees. may i have brainlest

6 0

3 years ago

Graph that represents y=4^2+3

marissa [1.9K]

Y=19, It's a straight horizontal line.

4 0

4 years ago

−8 = 3+t again sorry if im hurting yo brain

Oduvanchick [21]

Answer:

-11

Step-by-step explanation:

-8 = 3 + t

-8 - 3 = t

-11 = t

Hope this helps :)

6 0

3 years ago

lana [24]

Answer:

Part A:

To find the total length of the two sides you want to add them together:

(3x^2-2x-1)+(9x+2x^2-2)= you want to combine all like terms

3x^2+2x^2=5x^2, you add your coefficients and keep the exponents the same

-2x+9x=7x, you would combine like terms

-1-2=-3, you would subtract according to Keep, Change, Change

You now have:

5x^2+7x-3= Sides A+B

5x^2+7x-3

Part B:

To find the length of the third side you want to take the perimeter of the triangle and subtract it from our answer in part A

(5x^3+4x^2-x-3)-(5x^2+7x-3)

When subtraction polynomials we want to change the subtraction sign to addition and change the signs of the other number to the opposite sign to prevent making mistakes from subtraction, so you're new equation will look like this:

(5x^3+4x^2-x-3)+(-5x^2-7x+3)

Now we add all like terms again

5x^3, doesn't combine with any others so we leave it the same

4x^2-5x^2=-x^2, subtract them but remember to keep the exponents the same

-x-7x=-8x, again subtract terms but keep variable

-3+3=0, they cancel out so we don't have to worry about putting anything for this one

So now we are left with

5x^3-x^2-8x as our length for the third side

Third side equals 5x^3-x^2-8x

Part C:

For part A we added to get the total of sides B and A

For part B we subtracted the total perimeter from the total lengths of B and A, to figure out what C equals

Hope this helps ;)

4 0

4 years ago

Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.â Suppose a small group of 11 Allen's humming

alexira [117]

Answer:

$3.15-1.28\frac{0.38}{\sqrt{11}}=3.003$

$3.15+ 1.28\frac{0.38}{\sqrt{11}}=3.297$

So on this case the 80% confidence interval would be given by (3.003;3.297)

And the margin of error is given by:

$ME = 1.28\frac{0.38}{\sqrt{11}}= 0.147$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=3.15$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=0.38$ represent the population standard deviation

n=11 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.80 or 80%, the value of $\alpha=0.2$ and $\alpha/2 =0.1$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NOR.INV(0.1,0,1)".And we see that $z_{\alpha/2}=1.28$

Now we have everything in order to replace into formula (1):

$3.15-1.28\frac{0.38}{\sqrt{11}}=3.003$

$3.15+ 1.28\frac{0.38}{\sqrt{11}}=3.297$

So on this case the 80% confidence interval would be given by (3.003;3.297)

And the margin of error is given by:

$ME = 1.28\frac{0.38}{\sqrt{11}}= 0.147$

8 0

3 years ago