Question

Find the x-intercepts of the graph of y=x^2+4x-45

Answer 1

Answer:

(-9, 0) (5, 0)

Step-by-step explanation:

if we set y to 0, then we get:

0 = $x^{2}$ + 4x - 45

Now, we have to find what the x value is to equal 0.

0 = $-9^{2}$ + 4(-9) - 45

0 = 81 - 36 - 45

0 = 45 - 45

0 = $5^{2}$ + 4(5) - 45

0 = 25 + 20 - 45

0 = 45 - 45