Answer:
1. The enzyme __glycogen phosphorylase ______ removes terminal glucose residues from glycogen by cleaving __Alpha (1,4)______ linkages.2. Enzyme activity stops when the enzyme reaches a point __four___ glucose residues from a branch point, which is a(n) _alpha (1,6)______ linkage.3. The __transferase______ of the debranching enzymes moves three glucose residues to another branch, connecting them by a(n) __alpha(1,4)______ linkage.4. The _glucosidase_______ activity of the debranching enzyme removes the glucose at its _alpha (1,6)_______ linkage.5. The enzyme glycogen phosphorylase________ continues removing terminal glucose residuesAnswer Choices: Glucosidase, Phosphoglucomutase, three, four, glycogen phosphorylase, alpha (1,6), alpha (1,4), transferase
The answer to this question is D: Psychoactive. It is the world's most widely consumed psychoactive drug.
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There will be excessive flow of saliva for a short amount of time .
Answer:
The genetic information of living organisms is sequenced in DNA, which allows inheritable factors to be transmitted with each replication process. Proteins play a very important role by intervening in their metabolism during the translation and transcription of information. .
eukaryotic and prokaryotic organisms have different evolutionary sequelae that are reflected in the mechanisms they use for DNA translation, such as in the initial stages, lengthening and termination of sequencing, these differences are imparted by the order of the genes, the ribosome and its structural form and the promoter sequences.
In this way we can conclude that although the eukaryotic genes enter into a bacterium, the type of information that they take may arrive incomplete and this may generate subsequent defects for their operation, but there may be processes that guarantee a better transfer of information with the use of genetic engineering and enzyme management to introduce different bacterial genetic expressions with eukaryotic genes.