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2 years ago

5

One hundred and twenty three divided by four

1 answer:

Nat2105 [25]2 years ago

8 0

The answer to the question is 30.75

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F(x)=x 3−9xf, left parenthesis, x, right parenthesis, equals, x, cubed, minus, 9, x What is the average rate of change of f over

mel-nik [20]

Answer:

$A(x) = 243$

Step-by-step explanation:

Given

$f(x) = x^3 - 9x$

$Interval: (12,6)$

Required

Determine the average rate of change

Average rate is calculated as thus;

$A(x) = \frac{f(b) - f(a)}{b - a}$

<em>In this case; b = 12 and a = 6</em>

Calculating f(12)

$f(12) = 12^3 - 9 * 12$

$f(12) = 1728 - 108$

$f(12) = 1620$

Calculating f(6)

$f(6) = 6^3 - 9 * 6$

$f(6) = 216 - 54$

$f(6) = 162$

Substitute 12 for b and 6 for a in $A(x) = \frac{f(b) - f(a)}{b - a}$

$A(x) = \frac{f(12) - f(6)}{12 - 6}$

Substitute values for f(6) and f(12)

$A(x) = \frac{1620 - 162}{12 - 6}$

$A(x) = \frac{1458}{ 6}$

$A(x) = 243$

4 0

2 years ago

A=1+Prt solve for p

lilavasa [31]

$A=1+Prt\\\\Prt=A-1\\\\P=\dfrac{A-1}{rt}$

4 0

3 years ago

Which of the following sets contain all roots of the polynomial

Zarrin [17]

All these given roots are contained in option C.

The given equation is :

$9x^{3}+9x^{2}-4x-4=0$

$9x^{2}(x+1)-4(x+1)=0$

$(9x^{2}-4)(x+1)=0$

$9x^{2}-4=0,x+1=0$

$x^{2}=\frac{4}{9},x=-1$

$x=\frac{2}{3},x=-1$

Roots = $-1,\frac{-2}{3} ,\frac{2}{3}$

Hence these lie in between $(\frac{-3}{2} ,\frac{3}{2})$

8 0

2 years ago

90% of what number is 57

aliina [53]

To solve this, set up the equation, 90% of x being .9*x=57. Then, solve for x, x=57/.9= $6 \frac{1}{3}$ =6.333

4 0

3 years ago

The table shows the test scores of students who studied for a test as a group (Group A) and students who studied individually (G

blagie [28]

Answer:

Option B

Both distributions are nearly symmetric, so the mean and the standard deviation are the best measures for comparison.

Step-by-step explanation:

7 0

3 years ago

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