Minimum point of the quadratic x^2+6x-2
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Hey there :)
y =
Since this line is parallel to the line to be found, both have the same slope:
Coordinates: ( - 9 , - 2 )
y - ( -2 ) = ( x - ( -9 ) )
y =
Since this line is parallel to the line to be found, both have the same slope:
Coordinates: ( - 9 , - 2 )
y - ( -2 ) =
divisions between $389$ and $390$ so each division is $\frac{390-389}{10}=0.1$
A is 8 division from $389$, so, A is $389+8\times 0.1=389.8$
similarly, C is one division behind $389$ so it is $389-1\times 0.1=388.9$
and B is $390.3$