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3 years ago

9

If your teacher gave you instruction for constructing a regular pentagon inscribed in a circle, you would expect the pentagon to

be ____ of the circle

1 answer:

zaharov [31]3 years ago

3 0

Touching the perimeter

Hope this helps :)

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10 x 2 tens = tens =

Rama09 [41]

10 x 2 = 20 (twenty)

4 0

3 years ago

Read 2 more answers

The population at a football stadium is 4,068 people.The ratio of men to women in the stadium is 5:4.How many women are at the s

saveliy_v [14]

<h3>✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽</h3>

➷ 5 + 4 = 9

4068/9 = 452

4 x 452 = 1808

There are 1808 woman at the stadium

<h3><u>✽</u></h3>

➶ Hope This Helps You!

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➶ Have A Great Day ^-^

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4 0

4 years ago

You have $95 in your bank account. Each week you plan to deposit $9 from your allowance and $10 from your paycheck. The equat

kotykmax [81]

Answer:

7 weeks

Step-by-step explanation:

b=95+(10+9)w

Combine like terms

b=95+(19)w

Let b = 220

220 = 95 + 19w

Subtract 95 from each side

220-95 = 19w

125 = 19w

Divide each side by 19

125/19 = w

6.578947368

Round up

After 7 week

8 0

3 years ago

Please Help!!!!!! it's due this morning

zhuklara [117]

Answer:

Check the solution in both equations. The solution is ( − 1, 2). Solve the system by graphing: {− x + y = 12 x + y = 10 . Solve the system by graphing: {2x + y = 6 x + y = 1 . In all the systems of linear equations so far, the lines intersected and the solution was one point.

Hope it helps!!!

6 0

3 years ago

In Exercises 10 and 11, points B and D are points of tangency. Find the value(s) of x.<br>

Lemur [1.5K]

In both cases,

$AB^2=AD^2$

(as a consequence of the interesecting secant-tangent theorem)

So we have

10.

$(4x+7)^2=(6x-3)^2$

$16x^2+56x+49=36x^2-36x+9$

$20x^2-92x-40=0$

$5x^2-23x-10=0$

$(5x+2)(x-5)=0\implies\boxed{x=5}$

(omit the negative solution because that would make at least one of AB or AD have negative length)

11.

$(4x^2-18x-10)^2=(x^2+x+4)^2$

$16x^4-144x^3+244x^2+360x+100=x^4+2x^3+9x^2+8x+16$

$15x^4-146x^3+235x^2+352x+84=0$

$(x-7)(3x+2)(5x^2-17x-6)=0\implies\boxed{x=-\dfrac23\text{ or }x=7}$

(again, omit the solutions that would give a negative length for either AB or AD)

7 0

3 years ago