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alex41 [277]
3 years ago
9

If your teacher gave you instruction for constructing a regular pentagon inscribed in a circle, you would expect the pentagon to

be ____ of the circle
Mathematics
1 answer:
zaharov [31]3 years ago
3 0

Touching the perimeter

Hope this helps :)


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A soccer field is a rectangle 48 meters wide and 55 meters long. The coach asks players to run from one corner to the corner dia
Sindrei [870]

Answer:

Distance = 73 m

Step-by-step explanation:

Given that,

The length of a rectangle = 48 m

The width of a rectangle = 55 m

We need to find the diagonal distance. We can use the Pythagoras theorem to find it.

d^2=48^2+55^2\\\\d=\sqrt{5329}\\\\d=73\ m

So, the required distance is equal to 73 m.

5 0
3 years ago
Which expression is a perfect cube?<br> -8^21y^8<br> -64x^64y^64<br> -125x^9y^20<br> -126x^9y^18
yanalaym [24]
Hello,
Please, see the attached file.
Thanks.

6 0
3 years ago
If A(-5,7), B(-4,-5), C(-1,-6) and D(4,5) are the vertices of a quadrilateral, find the area of the quadrilateral ABCD.
MrMuchimi
After plotting the quadrilateral in a Cartesian plane, you can see that it is not a particular quadrilateral. Hence, you need to divide it into two triangles. Let's take ABC and ADC.

The area of a triangle with vertices known is  given by the matrix
M = \left[\begin{array}{ccc} x_{1}&y_{1}&1\\x_{2}&y_{2}&1\\x_{3}&y_{3}&1\end{array}\right]

Area = 1/2· | det(M) |
        = 1/2· | x₁·y₂ - x₂·y₁ + x₂·y₃ - x₃·y₂ + x₃·y₁ - x₁·y₃ |
        = 1/2· | x₁·(y₂ - y₃) + x₂·(y₃ - y₁) + x₃·(y₁ - y₂) |

Therefore, the area of ABC will be:
A(ABC) = 1/2· | (-5)·(-5 - (-6)) + (-4)·(-6 - 7) + (-1)·(7 - (-5)) |
             = 1/2· | -5·(1) - 4·(-13) - 1·(12) |
             = 1/2 | 35 |
             = 35/2

Similarly, the area of ADC will be:
A(ABC) = 1/2· | (-5)·(5 - (-6)) + (4)·(-6 - 7) + (-1)·(7 - 5) |
             = 1/2· | -5·(11) + 4·(-13) - 1·(2) |
             = 1/2 | -109 |
<span>             = 109/2</span>

The total area of the quadrilateral will be the sum of the areas of the two triangles:

A(ABCD) = A(ABC) + A(ADC) 
               = 35/2 + 109/2
               = 72
8 0
3 years ago
Quinn is flying a kite. The angle of elevation formed by the kite string and the ground is 40°, and the kite string forms a stra
emmasim [6.3K]

The distance between the ground and the kite to the nearest foot is 64 ft.

<h3>What is a right angle triangle?</h3>

A right angle triangle is a triangle that has one of its sides as 90 degrees. The situation forms a right angle triangle.

Hence,

The length of the kite string is the hypotenuse side of the triangle formed.

The height between the ground and the kite is the opposite side of the triangle formed.

Therefore, using trigonometric ratio,

sin 40 = opposite / hypotenuse

sin 40 = h / 100

cross multiply

h = 100 sin 40

h = 100 × 0.64278760968

h = 64.2787609687

h = 64 ft

Therefore, the distance between the ground and the kite to the nearest foot is 64 ft.

learn more on right triangle here: brainly.com/question/27482803

#SPJ1

7 0
2 years ago
F(x)=3x^2-x+2; [-3,1]
laiz [17]
Is it written like this?

6 0
3 years ago
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