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alex41 [277]
3 years ago
9

If your teacher gave you instruction for constructing a regular pentagon inscribed in a circle, you would expect the pentagon to

be ____ of the circle
Mathematics
1 answer:
zaharov [31]3 years ago
3 0

Touching the perimeter

Hope this helps :)


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kenny6666 [7]

The cost to equip all the stations in the chemistry lab is calculated as: $393.75.

<h3>How to Calculate Total Cost?</h3>

In this scenario, we are given the following:

Total number of stations = 21 stations

Length of rubber tubing each of the stations in the chemistry lab needs = 5 feet

Total length of rubber tubing needed for all stations in the chemistry lab = 21 × 5 = 105 feet

Cost of 1 rubber tubing = $6.25 per yard

Convert 5 feet to yard:

1 yard = 3 feet

x yard = 5 feet

x = (5 × 1)/3

x = 5/3 feet.

So, the cost of 1 rubber tubing = $6.25 per 5/3

Cost of total length of tubbing needed = (105 × 6.25)/5/3 = (105 × 6.25) × 3/5

Cost of total length of tubbing needed = $393.75

Therefore, the cost to equip all the stations in the chemistry lab is calculated as: $393.75.

Learn more about the How to Calculate Total Cost on:

brainly.com/question/2021001

#SPJ1

6 0
1 year ago
A dog has a leash on that is 4 meters long. What is the total area of the space where the dog can travel?
Mashcka [7]
There is no limit to the area that the dog can access and explore. It can go anywhere it wants to, and simply drag the leash behind. My dogs do it all the time. Now if you were to fasten the free end if the leash to a stake in the ground, then the situation would be a completely different one. Then the dog would be restricted to the circle centered at the stake with radius=4 meters. The area of such a circle is 16 pi square meters.
6 0
3 years ago
Evaluate the expression when m= -2.8 and n=-6.3.<br> 4n - 6m
Alex73 [517]
Answer is 42, hope this helps
5 0
2 years ago
Find the value of tan(sin^-1(1/2))
suter [353]

If you know that \sin\dfrac\pi3=\dfrac12, then you know right away

\tan\left(\sin^{-1}\dfrac12\right)=\tan\dfrac\pi3=\dfrac1{\sqrt}3=\dfrac{\sqrt3}3

###

Otherwise, you can derive the same result. Let \theta=\sin^{-1}\dfrac12, so that \sin\theta=\dfrac12. \sin^{-1} is bounded, so we know -\dfrac\pi2\le\theta\le\dfrac\pi2. For these values of \theta, we always have \cos\theta\ge0.

So, recalling the Pythagorean theorem, we find

\cos^2\theta+\sin^2\theta=1\implies\cos\theta=\sqrt{1-\sin^2\theta}=\sqrt{1-\left(\dfrac12\right)^2}=\dfrac{\sqrt3}2

Then

\tan\theta=\tan\left(\sin^{-1}\dfrac12\right)=\dfrac{\sin\theta}{\cos\theta}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}=\dfrac{\sqrt3}3

as expected.

5 0
3 years ago
Read 2 more answers
Which value is the furthest from 0 on the number line?
evablogger [386]

Answer:-21.5

Step-by-step explanation:

It’s the furthest

3 0
3 years ago
Read 2 more answers
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