Answer:
Step-by-step explanation:
The point of this question is to find out the point where two lines intersect. First we need to get the equation of those lines
Slope of line 1:
(Yb -Ya)/(Xb - Xa) =
(-10 - (-14))/(-1 - (-3)) =
4/2 =
2
Use that slope to find the Y-intercept of line 1
y = 2x + b
-14 = 2(-3) +b
-14 = -6 + b
-8 = b
Therefore Line 1 is:
y = 2x - 8
Slope of line 2
(11 - 13)/(-1 - (-3)) =
-2/2 =
-1
Y-intercept of line 2
y = -x + b
13 = -(-3) +b
13 = 3 + b
10 = b
Therefore line 2 is
y = -x + 10
Now we have 2 equations to solve for the coordinates x and y
y = 2x - 8
y = -x + 10
Substitute y out in one of the equations
2x - 8 = -x + 10
3x = 18
x = 6
Plug x into one of the equations
y = 2(6) - 8
y = 12 - 8
y = 4
Therefore the solution is:
x=6, y=4
Answer:
the length of RS to the nearest tenth of a foot is 240.6ft
1. (5+23)+65 = (5+65)+23 = 70+23 = 93 (D)
2. -(4x-7) = -4X+7 (C)
3. 2(6X+9) = 12X+18 (B)
4. 5(X-3) = 35
X-3 = 35/5
X-3 = 7
SO X= 7+3 = 10
THEN NO
9 IS NOT A SOLUTION
Answer: -1 would be -d
0 -> d
1 -> f
2 -> stays same
(if this is not the right answer I'm sorry because i learned this awhile ago
