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3 years ago

Can someone help me please

Mathematics

1 answer:

Vesna [10]3 years ago

8 0

Answer:

#5) Its line “k”

Well to solve this you need to know what negative slopes are.

They decrease from height from left to right

And also a slope is always calculated like this

rise -> run

Think of it like a bed.

You have to wake up which means you have to rise and then you run to do whatever it is you gotta do.

Rise is going vertical and run is going horizontal.

So for line K you have it because since its negative its -3/1 so technically its -3 rise(basically fall since its negative), 1 run (right).

#6) 1/2 is the slope of line N. Or (c)

Well n is a potsive slope so we can automatically remove a and b.

And we can count like this, it started from the orgin it looks like (but you can use any given point really) and then just follow it, rise 1 and run 2. Rise 2 and run 3 doesn’t work so it has to be 1.2 or (c)

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What is the answer??

denis-greek [22]

Answer:

10a²+5ab+2b²

Step-by-step explanation:

Start by combining like terms aka the ones that match:

Step 1: (4a²-5ab-6b²) + (10ab+6a²+8b²)

Step 2: (10a²-5ab-6b²) + (10ab+8b²)

Step 3: (10a²+5ab-6b²+8b²)

Final answer: 10a²+5ab+2b²

In step 1, I added the 4 and 6. In step 2, I added -5 and 10. In step 3, I added -6 and 8. For each I attached the proper ending (a², ab, and b²).

I hope this clears some confusion!

3 0

3 years ago

12. A research study was conducted to estimate the number of white perch (a type of fish) in a Midwestern lake. 300 perch were c

Artyom0805 [142]

Answer:

If the scientist’s estimate about the number of fish in the lake is correct, then it is 44% likely to get 20 perch out of 50 with a tag.

Step-by-step explanation:

Let p be the proportion of tagged white perch in the Midwestern lake.

Scientist's claim is that p= $\frac{300}{1000} =0.30$

Let's test this hypothesis as:

$H_{0}:$ p=0.30

$H_{a}:$ p≠0.30

P-value of the test statistic will give the likelihood of getting 20 perch out of 50 with a tag if the scientist's estimate ( $H_{0}$ ) is true.

Test statistic can be calculated using the equation

$z=\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } }$ where

p(s) is the sample proportion of white perch ( $\frac{20}{50} =0.25$ )

p is the proportion assumed under null hypothesis. (0.30)

N is the sample size (50)

Then $z=\frac{0.25-0.30}{\sqrt{\frac{0.30*0.70}{50} } }$ ≈ -0.77

Two tailed p-value of the test statistic is ≈ 0.44

Thus if the scientist’s estimate about the number of fish in the lake is correct, (p=0.30) then it is 44% likely to get 20 perch out of 50 with a tag.

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4 years ago

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Alenkinab [10]

Answer:

3.3 was as far of miles. .

8 0

3 years ago

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