I’ll check it give me a minute I’m mainly writing this so I know to come to this just sec
Answer:
Ok, as i understand it:
for a point P = (x, y)
The values of x and y can be randomly chosen from the set {1, 2, ..., 10}
We want to find the probability that the point P lies on the second quadrant:
First, what type of points are located in the second quadrant?
We should have a value negative for x, and positive for y.
But in our set; {1, 2, ..., 10}, we have only positive values.
So x can not be negative, this means that the point can never be on the second quadrant.
So the probability is 0.
X weight 131
---- = -------------
18.8% 100%
Cross multiply and get 24.6 pounds
A tranversal is a line that cuts and divides other lines proportionately
A) 2
B) DNE
C) -2
I hope this answers your question but I’m not so sure of my answer!
