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2 years ago

Determine the slope from the two points given: (1,1) and (3,11)

Mathematics

1 answer:

bekas [8.4K]2 years ago

3 0

Final Answer M= 4,12 i think this is adding

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Someone please help me!!

eduard

On what do you need help

4 0

3 years ago

Creating an Exponential Model

belka [17]

Answer:

P = $300

r = 0.15

n = 12

$544.61 (to the nearest cent)

$P(1+r)^t$

$524.70 (to the nearest cent)

Step-by-step explanation:

P = principal amount = $300

r = annual interest rate in decimal form = 15% = 15/100 = 0.15

n = number of times interest is compounded per unit t = 12

How much she'll owe in 4 years

P = 300

r = 0.15

n = 12

t = 4

$P(1+\frac{r}{n})^{nt}=300(1+\frac{0.15}{12})^{12 \times 4}$

= $544.61 (to the nearest cent)

Yearly compounding interest rate

$P(1+r)^t$

How much she'll owe in 4 years at yearly compounding interest

$P(1+r)^t=300(1+0.15)^4$

= $524.70 (to the nearest cent)

7 0

2 years ago

Which is the correct answers? (more than one)

viktelen [127]

B True because both graphs approaches x=0 but never touches it

E True if you just graph it out you can see that graph of g is going down and the graph of x is going up

A false because neither of the equations have a y intercept they have asymptote of x=0

C false because it is also a reflection across the x axis

D incorrect is because they both have domain {0<x<♾}

Hope this helped!

6 0

2 years ago

Of the 120 rooms in a hotel, 55% are single bed rooms, 30% are double bed rooms and the rest are deluxe rooms. How many deluxe r

Nat2105 [25]

Hey there !

Check the attachment.
Hope it helps you :)

6 0

3 years ago

Drag the tiles to the correct boxes to complete the palrs.

Brut [27]

Answer:

(f+g)(2) = 4

(f-g)(4) = 8

(f ÷g)(2) = 7

(f x g)(1) = 0

Step-by-step explanation:

We are given these following functions:

$f(x) = 2x + 3$

$g(x) = x - 1$

(f+g)(2)

$(f+g)(x) = f(x) + g(x) = 2x + 3 + x - 1 = 3x - 2$

At $x = 2$

$(f+g)(2) = 3(2) - 2 = 6 - 2 = 4$

Then

(f+g)(2) = 4

(f-g)(4)

$(f-g)(x) = f(x) - g(x) = 2x + 3 - (x - 1) = 2x + 3 - x + 1 = x + 4$

At x = 4

$(f-g)(4) = 4 + 4 = 8$

Then

(f-g)(4) = 8

(f ÷g)(2)

$(f \div g)(x) = \frac{f(x)}{g(x)} = \frac{2x+3}{x-1}$

At x = 2

$(f \div g)(2) = \frac{7}{1} = 7$

Then

(f ÷g)(2) = 7

(f x g)(1)

$(f \times g)(x) = f(x)g(x) = (2x+3)(x-1) = 2x^2 -2x + 3x - 3 = 2x^2 + x - 3$

Then

$(f \times g)(1) = 2(1)^2 + 1 - 3 = 3 + 1 - 3 = 0$

(f x g)(1) = 0

4 0

3 years ago