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Zolol [24]
3 years ago
15

There exists a linear function f(x) such that f(6) = 8, f(2)=20, and f(a) = 16. What is the value of 2a?

Mathematics
1 answer:
atroni [7]3 years ago
3 0

Answer:

a = 10/3.

Step-by-step explanation:

We write the linear function as follows:

f(x) = mx + b   where m is the slope and b is the y-intercept.

f(6) = 6m + b = 8

f(2) = 2m + b = 20    Subtracting these 2 equations:

4m = -12

m = -3.

and  -3 * 2 + b = 20 so:

b =   20 + 6 = 26.

So we have the linear function:

f(x) = -3 x + 26

f(a) = 16 = -3 a + 26

-3 a = 16-26

a = -10 * -3 =  10/3.

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Round this however you need to.

=================================================

Explanation:

I'm assuming you want to find the value of x, which your diagram is showing to be the length of segment QR.

If so, then we'll need to find the measure of angle Q first. Using the law of sines, we get the following:

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----------------

Now if Q = 42.9693397461 approximately, then angle P is

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