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Zolol [24]
3 years ago
15

There exists a linear function f(x) such that f(6) = 8, f(2)=20, and f(a) = 16. What is the value of 2a?

Mathematics
1 answer:
atroni [7]3 years ago
3 0

Answer:

a = 10/3.

Step-by-step explanation:

We write the linear function as follows:

f(x) = mx + b   where m is the slope and b is the y-intercept.

f(6) = 6m + b = 8

f(2) = 2m + b = 20    Subtracting these 2 equations:

4m = -12

m = -3.

and  -3 * 2 + b = 20 so:

b =   20 + 6 = 26.

So we have the linear function:

f(x) = -3 x + 26

f(a) = 16 = -3 a + 26

-3 a = 16-26

a = -10 * -3 =  10/3.

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F(x)= <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B4x%20-%207%7D%7B10%7D%20" id="TexFormula1" title=" \frac{4x - 7}{10} "
Naily [24]

Answer:

To find f-¹(x) of f(x) equate f(x) to y

That's

f(x) = y

So we have

y =  \frac{4x - 7}{10}

Next interchange the variables that's x becomes y and y becomes x

That's

x =  \frac{4y - 7}{10}

Next make y the subject

Cross multiply

We have

4y - 7 = 10x

Move -7 to the right side of the equation

4y = 10x + 7

Divide both sides by 4

We have the final answer as

y =  \frac{10x + 7}{4}

So

f ^{ - 1} (x) =  \frac{10x + 7}{4}

Hope this helps you

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