Answer:
a) ![r=\frac{4(333)-(200)(5.37)}{\sqrt{[4(12000) -(200)^2][4(9.3501) -(5.37)^2]}}=0.9857](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B4%28333%29-%28200%29%285.37%29%7D%7B%5Csqrt%7B%5B4%2812000%29%20-%28200%29%5E2%5D%5B4%289.3501%29%20-%285.37%29%5E2%5D%7D%7D%3D0.9857)
The correlation coefficient for this case is very near to 1 so then we can ensure that we have linear correlation between the two variables
b) 
Now we can find the means for x and y like this:
So the line would be given by:
Step-by-step explanation:
Part a
The correlation coeffcient is given by this formula:
![r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7Bn%28%5Csum%20xy%29-%28%5Csum%20x%29%28%5Csum%20y%29%7D%7B%5Csqrt%7B%5Bn%5Csum%20x%5E2%20-%28%5Csum%20x%29%5E2%5D%5Bn%5Csum%20y%5E2%20-%28%5Csum%20y%29%5E2%5D%7D%7D)
For our case we have this:
n=4 
The correlation coefficient for this case is very near to 1 so then we can ensure that we have linear correlation between the two variables
Part b
Where:
With these we can find the sums:
And the slope would be:
Now we can find the means for x and y like this:
And we can find the intercept using this:
So the line would be given by:
48 develop a fault out of the total built which is 2400 therefore
48/2400
If needs to be simplified then 1/50
1700 that is due in 14 days with a fee of 100$ because it’s a shorter time period
Answer: 27 dogs were seen at the clinic on monday.
27/45 = 0.6
0.6 = 60%
Answer:
The probability that all will last at least 30,000 miles is 0.3164.
Step-by-step explanation:
Consider the provided information.
For a particular tire brand, the probability of wearing out before 30,000 miles is 0.25. Someone who buys a set of four of these tires,
That means the probability of not wearing out is 1-0.25 = 0.75
Now use the binomial distribution formula.
Substitute p = 0.25, q=0.75, r=4 and n=4
The probability that all will last at least 30,000 miles is 0.3164.
