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olga nikolaevna [1]
3 years ago
8

Samples of laboratory glass are in small, lightpackaging or heavy, large packaging. Suppose that 2% and 1% of thesample shipped

in small and large packages, respectively, breakduring transit. (a) If 60% of the samples are shipped in largepackages and 40% are shipped in small packages, what proportion ofsamples break during shipment? (b) Also, if a sample breaks duringshipment, what is the probability that it was shipped in a smallpackage?
Mathematics
1 answer:
Aleks [24]3 years ago
5 0

Answer:

a) 1.4% of the samples break during shipment

b) the probability is 4/7 ( 57.14%)

Step-by-step explanation:

a) defining the event B= the sample of laboratory glass breaks , then the probability is:

P(B)= probability that sample is shipped in small packaging * probability that the sample breaks given that was shipped in small packaging +  probability that sample is shipped in large packaging * probability that the sample breaks given that was shipped in large packaging = 0.40* 0.02 + 0.60*0.01 = 0.014

b) we can use the theorem of Bayes for conditional probability. Then defining the event S= the sample is shipped in small packaging . Thus we have

P(S/B)= P(S∩B)/P(B) = 0.40* 0.02 / 0.014= 4/7 ( 57.14%)

where

P(S∩B)= probability that sample is shipped in small packaging and it breaks

P(S/B)= probability that sample was shipped in small packaging given that is broken

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17. (a) The formula with CP subject is CP=\frac{SP}{1.1}

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(c) The GST of item is $5.95

Step-by-step explanation:

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Keywords: percentage, multiplication

Learn more about multiplication at:

  • brainly.com/question/10764770
  • brainly.com/question/1087090

#LearnwithBrainly

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Read 2 more answers
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UNO [17]

Answer:

Step-by-step explanation:

Hello!

The objective of this experiment is to test if two different foam-expanding agents have the same foam expansion capacity

Sample 1 (aqueous film forming foam)

n₁= 5

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S₁= 0.6

Sample 2 (alcohol-type concentrates )

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X[bar]₂= 6.8

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The statistic to use to make the estimation and the hypothesis test is the t-statistic for independent samples.:

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(X[bar]_1 - X[bar]_2) ± t_{n_1 + n_2 - 2}*Sa* \sqrt{\frac{1}{n_1}+\frac{1}{n_2} }

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b.

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H₀: μ₁ - μ₂= 0

H₁: μ₁ - μ₂≠ 0

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<u>Complete question</u>

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