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musickatia [10]
2 years ago
12

What is 0.42 10 times as much?

Mathematics
1 answer:
alukav5142 [94]2 years ago
4 0

Answer:

Answer is 4.2

Step-by-step explanation:

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What is the median of this set of data: 593, 588, 540, 434, 420, 398, 390, 375
Anna [14]
C. 427

The median is the middle number of all the data

Since there is an even number of data points the median is in between the middle two data points (434 and 420)

To find this: 434-420=14
14/2=7
434-7=427
420+7=427
8 0
2 years ago
Help me please asap
abruzzese [7]

Answer:

So the right answer is none

Step-by-step explanation:

-6≤1+3x

3x≥-7

x≥-2,33

-2,33>-5>-6>-11

so none of those are bigger then -2,33 and x is bigger then -2,33

3 0
2 years ago
while exercising victor walked 1/8 of a mile in 1/9 of an hour. at this rate, how far will he travelled after an hour?
ExtremeBDS [4]
1 and 1/8 of a mile is how far he’ll walk
8 0
3 years ago
Read 2 more answers
X–2 1/2=6 3/4. X=?<br><br> x – 3.23 = 0.77. X=?
Over [174]

Answer:

x= 105/4

x=4

Step-by-step explanation:

5 0
2 years ago
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Bags of pretzels are sampled to ensure proper weight. The overall average for the samples is 9 ounces. Each sample contains 25 b
77julia77 [94]

Answer:

The value is UCL  =  10.8  

Step-by-step explanation:

From the question we are told that

    The sample mean is  \= x  =  9 \  ounce

    The sample size is  n =  25

    The standard deviation is  \sigma =  3 \ ounce

Given that the sample size is not large enough i.e  n<  30  we will make use of the student t distribution table  

From the question we are told the confidence level is  99.7% , hence the level of significance is    

      \alpha = (100 -99.7 ) \%

=>   \alpha = 0.003

Generally the degree of freedom is  df =  n- 1

=>  df =  25 - 1

=>  df =  24  

Generally from the student t distribution table the critical value  of  \frac{\alpha }{2} at a degree of freedom of df =  24   is  

   t_{\frac{\alpha }{2} , 24 } = 3.0

Generally the margin of error is mathematically represented as  

      E = t_{\frac{\alpha }{2} , 24} *  \frac{\sigma }{\sqrt{n} }

=>     E = 3.0 *  \frac{3 }{\sqrt{25} }

=>     E =1.8

Gnerally the  upper control chart limit  for 99.7% confidence is mathematically represented as

         UCL  =  \= x  + E

=>      UCL  =  9 + 1.8  

=>      UCL  =  10.8  

     

4 0
2 years ago
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