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kvv77 [185]
3 years ago
11

Which activity can be used to modify the value of an existing cell in a datatable

Computers and Technology
1 answer:
stepladder [879]3 years ago
4 0

Answer:

The name of the activity is "Add Data Column".

Explanation:

Add data column activity is a part of the database that is used in used for adding a column in the database table. This activity also used in Windows.  

  • It provides attachment in windows activity by using Uipath studio.
  • The Uipath studio is used to connect with any application, that enables by windows, and to perform multiple operations on single user interface elements.
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Write a C++ program that manage the student’s grades. Starting with a fixed number of students (use 10 for simplicity) the user
BigorU [14]

Answer:

#include <iostream>

using namespace std;

float findAverage(double grades[], int numOfgrades) {

   float sum = 0;

   for ( int i = 0 ; i < numOfgrades; i++ ) {

       sum += grades[i];

   }

   return (sum / numOfgrades);

}

char findLetterGrade(double grades[], int numOfgrades) {

   char letter;

   if(findAverage(grades, numOfgrades) >= 90 && findAverage(grades, numOfgrades) <= 100)

       letter = 'A';

   else if(findAverage(grades, numOfgrades) >= 80 && findAverage(grades, numOfgrades) <= 89)

       letter = 'B';

   else if(findAverage(grades, numOfgrades) >= 70 && findAverage(grades, numOfgrades) <= 79)

       letter = 'C';

   else if(findAverage(grades, numOfgrades) >= 60 && findAverage(grades, numOfgrades) <= 69)

       letter = 'D';

   else if(findAverage(grades, numOfgrades) >= 0 && findAverage(grades, numOfgrades) <= 59)

       letter = 'F';

       

   return letter;

}

int main()

{

   int numOfgrades, grade;

   

   for (int i = 0; i < 10; i++) {

       cout<<"Enter the number of grades for student #" << i+1 <<": ";

       cin >> numOfgrades;

       double grades[numOfgrades];

       

       for (int j = 0; j < numOfgrades; j++) {

           cout<<"Enter the grade" << j+1 <<" for student #" << i+1 <<": ";

           cin >> grade;

           grades[j] = grade;

       }

       cout << "Student #" << i+1 << " got " << findLetterGrade(grades, numOfgrades) << endl;

   }

   

   return 0;

}

Explanation:

Create a function named findAverage that takes two parameters, grades array and numOfgrades

Inside the function, create a for loop that iterates through the grades and calculates the sum of the grades. Then, return the average, sum/numOfgrades

Create another function named findLetterGrade that takes two parameters, grades array and numOfgrades

Inside the function, check the average grade by calling the findAverage() function. Set the letter grade using the given ranges. For example, if the result returned from findAverage() function is between 80 and 89, set the letter to 'B'. Then, return the letter.

In the main:

Create a for loop that iterates for each student, in this case 10 students. Inside the loop:

Ask the user to enter the number of grades for student. Using this value, create a grades array.

Create another for loop (inner for loop) that will set the grades array using the values entered by the user.

When the inner loop is done, call the findLetterGrade() function passing the grades array and numOfgrades as parameter and print the result

5 0
3 years ago
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