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rewona [7]
3 years ago
15

Complete the sentence to identify advantages of top-down programming design. Choose all that apply.

Computers and Technology
2 answers:
Sati [7]3 years ago
7 0

Answer:

A,B,C

Explanation:

just gonna have to trust me :)

yanalaym [24]3 years ago
3 0

Answer:The original choice to write apply_fg so that it accepts function arguments is a good one, because it increases interoperability. When the callable arguments to apply_fg use a single protocol, we can easily exchange them: #include <functional> float log2(float); int a = apply_fg(5.Of, int b = apply_fg(3.14f,

Explanation:

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What does the label display when the user clicks the button? void btnSubmit_Click(object sender, EventArgs e) { int num1 = 3; in
erma4kov [3.2K]

Answer:

10

Explanation:

num1=3 and num2=2

num3=myproc(num1)+myproc(num2)

myproc(num1) results 6

myproc(num2) results 4

when we add both e get 10

6 0
2 years ago
If you created a variable called name, what data type would that value be? Group of answer choices a float a string a Boolean an
Semenov [28]

I think its an integer

8 0
2 years ago
Read 2 more answers
Given six memory partitions of 100 MB, 170 MB, 40 MB, 205 MB, 300 MB, and 185 MB (in order), how would the first-fit, best-fit,
nlexa [21]

Answer:

We have six memory partitions, let label them:

100MB (F1), 170MB (F2), 40MB (F3), 205MB (F4), 300MB (F5) and 185MB (F6).

We also have six processes, let label them:

200MB (P1), 15MB (P2), 185MB (P3), 75MB (P4), 175MB (P5) and 80MB (P6).

Using First-fit

  1. P1 will be allocated to F4. Therefore, F4 will have a remaining space of 5MB from (205 - 200).
  2. P2 will be allocated to F1. Therefore, F1 will have a remaining space of 85MB from (100 - 15).
  3. P3 will be allocated F5. Therefore, F5 will have a remaining space of 115MB from (300 - 185).
  4. P4 will be allocated to the remaining space of F1. Since F1 has a remaining space of 85MB, if P4 is assigned there, the remaining space of F1 will be 10MB from (85 - 75).
  5. P5 will be allocated to F6. Therefore, F6 will have a remaining space of 10MB from (185 - 175).
  6. P6 will be allocated to F2. Therefore, F2 will have a remaining space of 90MB from (170 - 80).

The remaining free space while using First-fit include: F1 having 10MB, F2 having 90MB, F3 having 40MB as it was not use at all, F4 having 5MB, F5 having 115MB and F6 having 10MB.

Using Best-fit

  1. P1 will be allocated to F4. Therefore, F4 will have a remaining space of 5MB from (205 - 200).
  2. P2 will be allocated to F3. Therefore, F3 will have a remaining space of 25MB from (40 - 15).
  3. P3 will be allocated to F6. Therefore, F6 will have no remaining space as it is entirely occupied by P3.
  4. P4 will be allocated to F1. Therefore, F1 will have a remaining space of of 25MB from (100 - 75).
  5. P5 will be allocated to F5. Therefore, F5 will have a remaining space of 125MB from (300 - 175).
  6. P6 will be allocated to the part of the remaining space of F5. Therefore, F5 will have a remaining space of 45MB from (125 - 80).

The remaining free space while using Best-fit include: F1 having 25MB, F2 having 170MB as it was not use at all, F3 having 25MB, F4 having 5MB, F5 having 45MB and F6 having no space remaining.

Using Worst-fit

  1. P1 will be allocated to F5. Therefore, F5 will have a remaining space of 100MB from (300 - 200).
  2. P2 will be allocated to F4. Therefore, F4 will have a remaining space of 190MB from (205 - 15).
  3. P3 will be allocated to part of F4 remaining space. Therefore, F4 will have a remaining space of 5MB from (190 - 185).
  4. P4 will be allocated to F6. Therefore, the remaining space of F6 will be 110MB from (185 - 75).
  5. P5 will not be allocated to any of the available space because none can contain it.
  6. P6 will be allocated to F2. Therefore, F2 will have a remaining space of 90MB from (170 - 80).

The remaining free space while using Worst-fit include: F1 having 100MB, F2 having 90MB, F3 having 40MB, F4 having 5MB, F5 having 100MB and F6 having 110MB.

Explanation:

First-fit allocate process to the very first available memory that can contain the process.

Best-fit allocate process to the memory that exactly contain the process while trying to minimize creation of smaller partition that might lead to wastage.

Worst-fit allocate process to the largest available memory.

From the answer given; best-fit perform well as all process are allocated to memory and it reduces wastage in the form of smaller partition. Worst-fit is indeed the worst as some process could not be assigned to any memory partition.

8 0
3 years ago
Discuss the economical challenges in software reuse using suitable examples.
Liula [17]

Answer: Reusing software device has some economical challenges such as:

  • Investment cost in reusing the device is considered as the extra cost.It  might require some extra components for the working to become usable
  • Requires skilled person who can develop and design the software to be used again.The creating and designing of new software design is comparatively easy but making the system reusable requires someone who has more designing skill who will be highly paid for the work
  • Cost of writing and reading of the software can also be considered as the economical challenge as the reused system created is to be studied by some other organization members or sources not familiar with the functioning. .

4 0
3 years ago
Consider the following code:
ICE Princess25 [194]

Answer: 3

Explanation:

Because X = 18 and our condition given to the code if > and < which do not match with the input so it prints 3.

4 0
3 years ago
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