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Kaylis [27]
3 years ago
10

A quiz consists of 3 true-or-false questions and 2 multiple choice questions. The multiple choice questions have 4 options each.

How many ways can a student complete the quiz?
A) 16 B)96 C)128 D)144
Mathematics
1 answer:
Murljashka [212]3 years ago
4 0
The answer would be B.96
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A car is traveling at a constant speed of 60 miles per hour. How many feet does it travel in 10 seconds?
Nat2105 [25]

Answer:

880 ft.

Step-by-step explanation:

<em>First! We have to establish how many feet the car travels per hour. </em>

60 <em>(number of miles per hour)</em> x 5280 <em>(number of feet in a mile) </em>= 316,800 <em>(number of feet in an hour)</em>

<em>Next, since we know that there are 60 minutes in an hour we are going to divide our "number of feet in an hour" by 60 to get the "number of feet in a minute"</em>

316,800 ÷ 60 = 5280

<em>Once again, we are going to divide our "number of feet in a minute" by 60 to get the "number of feet per second".</em>

5280 ÷ 60 = 88

<em>Finally! We will multiple our "number of feet per second" by 10 to get how many feet the car can travel in 10 seconds.</em>

88 × 10 = 880

<em>So! Our car can travel 880 feet in 10 seconds.</em>

Hope this Helps! :)

<em>Have any questions? Ask below in the comments and I will try my best to answer.</em>

-SGO

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5 0
3 years ago
To complete a job a crew of 8 people needs 18 days. How long will the same job be finished if the crew will have 9 people?
zavuch27 [327]

Answer:

16

Step-by-step explanation:

.

7 0
2 years ago
Read 2 more answers
6. a. Sixty students in a class took an examination in Physics and Mathematics. If 17 of them passed Physics only, 25 passed in
Ivahew [28]

Let C be the set of all students in the <u>c</u>lassroom.

Let P and M be the sets of students that pass <u>p</u>hysics and <u>m</u>ath, respectively.

We're given

n(C) = 60

n(P \cap M') = 17

n(P \cap M) = 25

n((P \cup M)') = n(P' \cap M') = 9

i. We can split up P into subsets of students that pass both physics and math (P\cap M) and those that pass only physics (P\cap M'). These sets are disjoint, so

n(P) = n(P\cap M) + n(P\cap M') = 25 + 17 = \boxed{42}

ii. 9 students fails both subjects, so we find

n(C) = n(P\cup M) + n(P\cup M)' \implies n(P\cup M) = 60 - 9 = 51

By the inclusion/exclusion principle,

n(P\cup M) = n(P) + n(M) - n(P\cap M)

Using the result from part (i), we have

n(M) = 51 - 42 + 25 = 34

and so the probability of selecting a student from this set is

\mathrm{Pr}(M) = \dfrac{34}{60} = \boxed{\dfrac{17}{30}}

7 0
2 years ago
I give free points and brainliest to the first one who says something because I feel nice today.
Eddi Din [679]

Answer: thank you

Step-by-step explanation:

abacnxBZCNxbnxv xzcbvxzc

5 0
2 years ago
Read 2 more answers
There are 36 dinosaurs pictured in Karmita's book. If 2/3 of them were plant eaters, how many were plant eaters.
UNO [17]
In order to solve your question, you first have to understand what 1/3 of 36 is. you can do that by dividing 36/3.

when you do this you get the answer of 12. 1/3 of 36 is 12.

to get the 2/3 part. Add 12 to the existing part that you have.

Therefore, you have 24 plant eaters.
5 0
2 years ago
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