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swat32
3 years ago
5

A milloniare estimates her wealth to be $2.2×10 to the nearst million dollars.what are the lower and upper bounds for the millio

niare's wealth​
Mathematics
1 answer:
Andrews [41]3 years ago
3 0

Answer:

2.2 x10= = 22.2 =22 million.

Step-by-step explanation:

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Veseljchak [2.6K]
SAS stand for side-angle-side. In order to know that these two triangles are similar you need to find the measure of side GH and MN
3 0
3 years ago
What point he plot to show how far he runs in 8 minutes and 12 minutes?​
Dmitriy789 [7]

Answer:

4

Step-by-step explanation:

because you subtract it.

8 0
3 years ago
Consider the parent function f(x) = x^2 and the transformed function f(x) =- 5(x - 4)^2 – 8. Identify the
madam [21]

Given:

The parent function is

f(x)=x^2

Consider the transformed function is g(x) instead of f(x) because both functions are different.

g(x)=-5(x-4)^2-8

Step-by-step explanation:

We have,

f(x)=x^2

g(x)=-5(x-4)^2-8

It can be written as

g(x)=-5f(x-4)-8            ...(i)

The translation is defined as

g(x)=kf(x+a)+b                .... (ii)

Where, k is stretch factor, a is horizontal shift and b is vertical shift.

If 0<|k|<1, then the graph compressed vertically by factor k and if |k|>1, then the graph stretch vertically by factor k.

If k is negative, then f(x) is reflected across the x-axis to get g(x).

If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.

If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.

On comparing (i) and (ii), we get

a=-4, f(x) shifts 4 units right.

b=-8, f(x) shifts 8 units down.

k=-5, it is negative so f(x) reflected across the x-axis.

|k|=|-5|=5>1, so f(x) stretched vertically by factor 5.

Therefore, the function f(x) reflected across the x-axis, stretched vertically by factor 5 and shifted 4 units right 8 units down to get g(x).

8 0
3 years ago
Solve the equation below.<br><br> 1.2m+0.65=5
andrew-mc [135]

Answer:

m = 3.625

Step-by-step explanation:

1.2m + 0.65 = 5

~Subtract 0.65 to both sides

1.2m = 4.35

~Divide 1.2 to both sides

m = 3.625

Best of Luck!

5 0
3 years ago
Put together, Dulcina and Tremaine have 129 total matchbooks. Tremaine's collection has 39 fewer matchbooks in it than Dulcina's
Anit [1.1K]

Answer:

Let the Dulcina's collection be 'x'

Let the Tremaine collection be 'x-39'

x + x - 39 =129

2x = 129 +39

2x = 168

x = 168/2

x = 84

Dulcina's collection = x = 84

Tremaine's collection = x - 39 = 84 - 39 = 45

7 0
3 years ago
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