For domain 2x sqrt(2+x)>0
x>0,2+x>0,x>-2 combining
we get x>2
f'(x)=[1/{2x sqrt(2+x)}][{2x/(2 sqrt(2+x))}+2 sqrt(2+x)]
Answer:
The equation of line with given points is 2Y - X - 5 = 0
Step-by-step explanation:
Given points are ( - 3 , 1) and (9 , 7)
Equation of line is y = mx +c
where m is the slop of line
Now m = 
Or, m = 
so, slop = 
∴ slop = 
Now the equation of line with points ( -3 , 1) and slop m is :
Y - y1 = m ( X - x1)
Or, Y - 1 = (X + 3)
Or, 2Y - X - 5 = 0
Hence The equation of line with given points is 2Y - X - 5 = 0 Answer
Answer:
x = 8.69
Step-by-step explanation:
we know that the perimeter of the dodecagon is 54, so each edge will be 54/12
54/12 = 4.5 cm
if we draw the lines to remove 6 vertices and form a hexagon, 6 triangles with 2 sides of 4.5 cm are formed.
we know that the angle of each vertex is 150 ° because it is a dodecagon
if we apply the law of cosines we can take the other side of the triangle, since we only need 2 side and the opposite angle to the side we want to know
a would be our x
b = 4.5
c = 4.5
A = 150°
a^2 = b^2 + c^2 - 2bc * cos (A)
x^2 = 4.5^2 + 4.5^2 - 2 * 4.5 * 4.5 * cos (150)
x^2 = 20.25 + 20.25 - 40.50 * -0.866
x^2 = 40.50 + 35.07
x = √ 75.57
x = 8.69
Marco rounded the hundredths place since after the decimal it is the tenths then the hundredths then the thousands place
You can download the answer here
bit.
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