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svet-max [94.6K]
3 years ago
8

How to divide a rectangle into 14 equal parts

Mathematics
1 answer:
Andrew [12]3 years ago
5 0

Answer:

A picture

Step-by-step explanation:

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Divide. simplify your answer (2x^4-6x^3+4x^2-3x)*(2x)
lbvjy [14]

Answer:

x^3-3x^2+2x-\frac{3}{2}

Step-by-step explanation:

We can divide polynomials by other polynomials by dividing each term by the denominator. Remember, when we divide a variable by itself, we must change the exponent in our answer according to exponent rules.

\frac{ (2x^4-6x^3+4x^2-3x)}{2x}=\frac{2x^4}{2x} -\frac{6x^3}{2x} +\frac{4x^2}{2x} -\frac{3x}{2x} =x^3-3x^2+2x-\frac{3}{2}


4 0
3 years ago
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I will give you the brainlist and 5 stars if you answer this. This is for simple probability.
lions [1.4K]

Answer:

d is false

Step-by-step explanation:

water = 14 and cola is 28

you are half as likely to select a water than cola

3 0
3 years ago
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please help me, Prove a quadrilateral with vertices G(1,-1), H(5,1), I(4,3) and J(0,1) is a rectangle using the parallelogram me
mestny [16]

Answer:

Step-by-step explanation:

We are given the coordinates of a quadrilateral that is G(1,-1), H(5,1), I(4,3) and J(0,1).

Now, before proving that this quadrilateral is a rectangle, we will prove that it is a parallelogram. For this, we will prove that the mid points of the diagonals of the quadrilateral are  equal, thus

Join JH and GI such that they form the diagonals of the quadrilateral.Now,

JH=\sqrt{(5-0)^{2}+(1-1)^{2}}=5 and

GI=\sqrt{(4-1)^{2}+(3+1)^{2}}=5

Now, mid point of JH=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

=(\frac{5+0}{2},\frac{1+1}{2})=(\frac{5}{2},1)

Mid point of GI=(\frac{5}{2},1)

Since, mid point point of JH and GI are equal, thus GHIJ is a parallelogram.

Now, to prove that it is a rectangle, it is sufficient to prove that it has a right angle by using the Pythagoras theorem.

Thus, From ΔGIJ, we have

(GI)^{2}=(IJ)^{2}+(JG)^{2}                             (1)

Now, JI=\sqrt{(4-0)^{2}+(3-1)^{2}}=\sqrt{20} and GJ=\sqrt{(0-1)^{2}+(1+1)^{2}}=\sqrt{5}

Substituting these values in (1), we get

5^{2}=(\sqrt{20})^{2}+(\sqrt{5})^{2} }

25=20+5

25=25

Thus, GIJ is a right angles triangle.

Hence, GHIJ is a rectangle.

Also, The diagonals GI=\sqrt{(4-1)^{2}+(3+1)^{2}}=5  and HJ=\sqrt{(0-5)^2+(1-1)^2}=5 are equal, thus, GHIJ is a rectangle.

6 0
3 years ago
I dont really understand this stuff
viva [34]
The area of a parallelogram is the base times the height.

Area and base is given so we can use that to solve for the height:
72 = 6* h

h = 72/6
h = 12

The height is 12 units.


8 0
3 years ago
The products of 0.42 with 0.2 can be written in fraction?
goblinko [34]
I believe it is yes. I think the right fraction is 84/1000. Let me know if this works and if not tell me
7 0
3 years ago
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