Question

At a bus station, buses begin their routes at 6.Am. The schedule for two of the buses is based on time intervals listen below

Answer 1

Answer:

They will both leave at 07:15am

Step-by-step explanation:

Given

$Start\ time = 6:00am$

$Bus\ A=75\ mins$

$Bus\ B=15\ mins$

Required

Next time both buses leave the station at the same time

To do this, we list out the multiples of 75 and 15.

We have:

$Bus\ A = 0,75, 150, 225, 300,375, 450, 525, 600 ....$

$Bus\ B =0, 15,30,45,60,75,90,105,120,135,150,165,180.....$

After the first departure at 06:00 am (0 minutes) for both buses respectively, the next time they both leave is after 75 minutes (common multiple)

So, the time is:

$Time = 6:00am + 75 mins$

$Time = 07:15am$