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Mekhanik [1.2K]
3 years ago
15

At a bus station, buses begin their routes at 6.Am. The schedule for two of the buses is based on time intervals listen below

Mathematics
1 answer:
kykrilka [37]3 years ago
3 0

Answer:

They will both leave at 07:15am

Step-by-step explanation:

Given

Start\ time = 6:00am

Bus\ A=75\ mins

Bus\ B=15\ mins

Required

Next time both buses leave the station at the same time

To do this, we list out the multiples of 75 and 15.

We have:

Bus\ A = 0,75, 150, 225, 300,375, 450, 525, 600 ....

Bus\ B =0, 15,30,45,60,75,90,105,120,135,150,165,180.....

After the first departure at 06:00 am (0 minutes) for both buses respectively, the next time they both leave is after 75 minutes (common multiple)

So, the time is:

Time = 6:00am + 75 mins

Time = 07:15am

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