Walk through writing a general formula for the midpoint between two points. ... I believe you would simply find the differences in x and y from the midpoint to the ... if point A is at (3,2) and the midpoint is at (-2,5), i would move 5 left and 3 up from A ... do u guys think this is easy? is this the easiest thing in geometry, im trying to ...
Answer:
7.3% of the bearings produced will not be acceptable
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Target value of .500 in. A bearing is acceptable if its diameter is within .004 in. of this target value.
So bearing larger than 0.504 in or smaller than 0.496 in are not acceptable.
Larger than 0.504
1 subtracted by the pvalue of Z when X = 0.504.
has a pvalue of 0.9938
1 - 0.9938= 0.0062
Smaller than 0.496
pvalue of Z when X = -1.5
has a pvalue of 0.0668
0.0668 + 0.0062 = 0.073
7.3% of the bearings produced will not be acceptable
The law of cosines states that:
c^2=a^2+b^2-2abcosC
You already have all the values for the variables with the exception of x so:
x^2=25+100-100cos60
x=√(125-100cos60)
x=√75
x≈8.66 to nearest one-hundredth...
70 x 100 = 7,000
Therefore, 70 hundred is equal to 7 thousands.
Answer:
24 munchkins.
Step-by-step explanation:
Let C be the number of chocolate and D be number of glazed donut holes in the original box.
We are told if Jacob ate 2 chocolate munchkins, then 1/11 of the remaining Munchkins would be chocolate. We can represent this information as:
We are also told if he instead added 4 glazed Munchkins to the original box, 1/7 of the Munchkins would be chocolate. We can represent this information as:
Upon substituting C's value from equation (2) in equation (1) we will get,
Let us have a common denominator on right side of equation.
Multiplying both sides of our equation by 7, we will get,
Multiplying both sides of our equation by 11, we will get,
Therefore, the total number of Munchkins in original box is 24.