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aksik [14]
3 years ago
11

Christine wants to buy strawberries and raspberries to bring to a party. Strawberries cost $1.65 per pound and raspberries cost

$2.25 per pound. She only has $15 to spend on berries. Which inequality represents the situation where she buys x pounds of strawberries and y pounds of raspberries?
Mathematics
1 answer:
Fudgin [204]3 years ago
3 0

Answer:

1.65x + 2.25y ≤ 15

Step-by-step explanation:

Strawberries = $1.65 per pound Raspberries = $2.25 per pound

Amount with Christine = $15

Let

pounds of strawberries = x

pounds of raspberries = y

PxQx + PyQy ≤ 15

1.65x + 2.25y ≤ 15

The inequality which represent the situation where she buys x pounds of strawberries and y pounds of raspberries is 1.65x + 2.25y ≤ 15

1.65x + 2.25y less than or equal to 15

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14. How much greater is the sum of the first 50 counting numbers greater than the sum of the first 100 counting numbers? a. 110
77julia77 [94]

Answer:

b. 3.775

Step-by-step explanation:

The question is worded incorrectly since the sum of the first 100 counting numbers is actually greater than the sum of the first 50 counting numbers.

The sum of any set of consecutive numbers of size 'n' is given by:

S = \frac{(A_1+A_n)*n}{2}

Where A1 is the first number on the set and An is the last number.

The sum of the first 100 counting numbers (1 through 100) is:

S_{100}= \frac{(1+100)*100}{2}=5,050

The sum of the first 50 counting numbers (1 through 50) is:

S_{50}= \frac{(1+50)*50}{2}=1,275

The difference between those two values is:

S_{100} -S_{50} =5,050-1,275=3,775

Therefore, the sum of the first 100 counting numbers is 3,775 greater than the sum of the first 50 counting numbers.

7 0
3 years ago
Help please 15 points up for grabs
Usimov [2.4K]

a) P(3) = \frac{11}{100} (or 0.11 or 11%)

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                                = \frac{12}{100} x 500

                                = 12 x 5

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emmasim [6.3K]

Answer:

Step-by-step explanation:

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k = constant of proportionality

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B = k(A²) / C³

B = kA²/C³

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2 years ago
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